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mixas84 [53]
3 years ago
14

Please answer! Explain all steps!

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0
We will be using the formulas:
speed=distance/time
time=distance/speed
distance=speed×time
First let's find out Diane's rate of swimming. We can measure this by finding the slope (y/x) of a given coordinate on the graph. One point is (10,15), so you do 15/10=1.5m/s
Now for Rick's rate of swimming, just take a pair of values from the table. 12.5/10=1.25m/s
By the way m/s is metres per second for this
So at a constant speed of 1.5m/s, Diane swam 150m in 150/1.5= 100 seconds, or 1 minute 40 seconds
And at a constant speed of 1.25m/s, Rick swam 150m in 150/1.25= 120 seconds, or 2 minutes.
So the difference between their two times is 20 seconds
Harlamova29_29 [7]3 years ago
3 0
From the grid on Diane's swim you can see that, for every two squares on the grid over the x-axis, it goes up 3 squares over the y-axis, it moves 2 to the right and then 3 up, and you get the next point.  What does that mean?  well, is a constant speed and thus the graph is a line, with a slope of 3 meters per 2 seconds, so her slope is 3/2 m/s.

now, for Rick's slope, we can just pick two points off of it, say, hmmm 10, 12.5 and 20, 25, and get the slope,

 \bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 10}} &,&{{ 12.5}}~) 
%  (c,d)
&&(~{{ 20}} &,&{{ 25}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{25-12.5}{20-10}\implies \cfrac{12.5}{10}\implies \cfrac{\frac{125}{10}}{10}
\\\\\\
\cfrac{\frac{125}{10}}{\frac{10}{1}}\implies \cfrac{125}{10}\cdot \cfrac{1}{10}\implies \cfrac{125}{100}\implies \cfrac{5}{4}\cdot \cfrac{meters}{second}

so Diane is doing 3 meters for every 2 seconds, and Rick is doing 5 meters for every 4 seconds.

how long will it be for each to do the 150 meters anyway?

\bf ~~~~~~~~~~~~~~Diane's\\\\
\begin{array}{ccll}
meters&seconds\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
3&2\\
150&x
\end{array}\implies \cfrac{3}{150}=\cfrac{2}{x}\implies x=\cfrac{150\cdot 2}{3}\implies x=100\\\\
-------------------------------\\\\

\bf ~~~~~~~~~~~~~~Rick's\\\\
\begin{array}{ccll}
meters&seconds\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
5&4\\
150&y
\end{array}\implies\cfrac{5}{150}=\cfrac{4}{y}\implies y=\cfrac{150\cdot 4}{5}\implies y=120

what's their difference?  well y - x.
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