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irinina [24]
3 years ago
10

Please only answer if your certain it will mean a lot I can give extra points or brain list if you like or a thanks please don’t

put anything Radom or a lie thank you

Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

Ms. Cortez earns 500 dollars for working 30 hours.  It's the last choice.

Step-by-step explanation:

You just have to substitute 30 into the equation in place of x, since x represents hours.

f(30) = 50 + 15(30)

f(30) = 50 + 450

f(30 = 500

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(3+8-4)×2-12
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Please help me with this geometry problem
Natalka [10]
You're looking for the volume of the prism.  The dead giveaway there is that you're looking for "cubic" measurement.  Cubic measures are indicators that the volume is being determined, just like "square feet" or inches, etc indicates area is being determined.  The volume for this prism is found by multiplying the length times the width times the height.  In decimal form, 45×30×40=54,000.  But that is in cubic inches and we want cubic feet.  So we will use dimensional analysis to convert that.  Setting up the DA looks like this, keeping in mind that there are 12 cubic inches in 1 cubic foot:  54,000in^3* \frac{1ft*1ft*1ft}{12in*12in*12in}.  The label of cubic inches cancels out leaving us with cubic feet, and doing the division there gives us 54,000/(12*12*12) which is 31.25 cubic feet.
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4 years ago
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Arisa [49]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the y intercept​
erica [24]

Step-by-step explanation:

Slope of line ST = Slope of line PQ = -3.

y = -3x + c

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Therefore the equation of line ST is y = -3x + 8 and the y-intercept is 8.

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

3 0
3 years ago
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