You're looking for the volume of the prism. The dead giveaway there is that you're looking for "cubic" measurement. Cubic measures are indicators that the volume is being determined, just like "square feet" or inches, etc indicates area is being determined. The volume for this prism is found by multiplying the length times the width times the height. In decimal form, 45×30×40=54,000. But that is in cubic inches and we want cubic feet. So we will use dimensional analysis to convert that. Setting up the DA looks like this, keeping in mind that there are 12 cubic inches in 1 cubic foot:

. The label of cubic inches cancels out leaving us with cubic feet, and doing the division there gives us 54,000/(12*12*12) which is 31.25 cubic feet.
Answer:
b is the aswer
Step-by-step explanation:
Step-by-step explanation:
Slope of line ST = Slope of line PQ = -3.
y = -3x + c
When x = 3, y = -1
=> (-1) = -3(3) + c, c = 8
Therefore the equation of line ST is y = -3x + 8 and the y-intercept is 8.
Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>
Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be
inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment
be a height on side
. Since this triangle is equilateral, the size of each internal angle will be
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
<h3>Area of of the circle that is not covered</h3>
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is
inches, the radius of this circle will also be
inches.
The area (in square inches) of a circle of radius
inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.