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marshall27 [118]
3 years ago
5

What is the purpose of a free body diagram

Physics
2 answers:
Amiraneli [1.4K]3 years ago
4 0
<span>A free body diagram is a representation of how the forces that are acting on a point or particle interact. You place your point at the origin and then draw your forces.


</span>
Inga [223]3 years ago
4 0

Answer:

The purpose of a free body diagram is to make  a visual representation of all the forces acting on an object.

In a free-body diagram, the object is represented at the centre; every force acting on the object is represented as an arrow, starting from the centre of the object, and with a length proportional to the magnitude of the force and direction equal to the direction of the corresponding force.

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"2.40 A pressure of 4 × 106N/m2 is applied to a body of water that initially filled a 4300 cm3 volume. Estimate its volume after
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Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

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2 years ago
A particle executes simple harmonic motion with an amplitude of 1.69 cm. At what positive displacement from the midpoint of its
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Answer: 0.0146m

Explanation: The formula that defines the velocity of a simple harmonic motion is given as

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Where v = linear velocity, A = amplitude = 1.69cm = 0.0169m, x = displacement.

The maximum speed of a simple harmonic motion is derived when x = A, hence v = ωA

One half of maximum speed = speed of motion

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ω cancels out on both sides of the equation, hence we have that

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0.00845 = √(0.0169² - x²)

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