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3 years ago

What is the purpose of a free body diagram

2 answers:

4 0

<span>A free body diagram is a representation of how the forces that are acting on a point or particle interact. You place your point at the origin and then draw your forces.

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Inga [223]3 years ago

4 0

Answer:

The purpose of a free body diagram is to make a visual representation of all the forces acting on an object.

In a free-body diagram, the object is represented at the centre; every force acting on the object is represented as an arrow, starting from the centre of the object, and with a length proportional to the magnitude of the force and direction equal to the direction of the corresponding force.

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A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. Wha

Vaselesa [24]

Answer:

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

$x(t) = A\cdot \cos (\omega \cdot t + \phi)$

Where:

$x(t)$ - Position of the mass with respect to the equilibrium position, measured in centimeters.

$A$ - Amplitude of the mass-spring system, measured in centimeters.

$\omega$ - Angular frequency, measured in radians per second.

$t$ - Time, measured in seconds.

$\phi$ - Phase, measured in radians.

The acceleration experimented by the mass is obtained by deriving the position equation twice:

$a (t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)$

Where the maximum acceleration of the system is represented by $\omega^{2}\cdot A$ .

The natural frequency of the mass-spring system is:

$\omega = \sqrt{\frac{k}{m} }$

Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

If $k = 12\,\frac{N}{m}$ and $m = 0.40\,kg$ , the natural frequency is:

$\omega = \sqrt{\frac{12\,\frac{N}{m} }{0.40\,kg} }$

$\omega \approx 5.477\,\frac{rad}{s}$

Lastly, the maximum acceleration of the system is:

$a_{max} = \left(5.477\,\frac{rad}{s})^{2}\cdot (12\,cm)$

$a_{max} = 359.970\,\frac{cm}{s^{2}}$

The maximum acceleration of the system is 359.970 centimeters per square second.

7 0

3 years ago

A car weighs 1323 N. what is its mass?

Shalnov [3]

If the car is on the moon, its mass is about 817 kg.

If it's on the Earth, its mass is about 135 kg.

6 0

3 years ago

Read 2 more answers

A rock is dropped from the edge of a cliff into a pool of water. Assume free-fall acceleration is 10 m/s per second, and air res

il63 [147K]

Answer:

20 m

Explanation:

From the equation of motion,

S = ut+1/2gt²................................. Equation 1

Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.

Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative

Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)

Substituting into equation 1

S = 0(2) + 1/2(10)(2)²

S = 5(4)

S = 20 m

Hence the height of the the cliff above the pool is 20 m

7 0

3 years ago

Which two charges of a magnet will attract?

ale4655 [162]

Answer:

The other end is called the south pole. When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges.

Explanation:

4 0

3 years ago

Read 2 more answers

Absolute differences between each observed mass and the accepted value,divided by the accepted value, multiplied by 100%

timama [110]

Answer:

The percentage error e% = Δm/m 100

Explanation:

The absolute error is the assessment with which measurements are made, it is given by the minimum reading value of a given instrument.

The accepted value is the value measured in an instrument. Or the one calculated by an experiment.

The percentage error is the ratio of the absolute error between the value of the average per 100

e% = Δm/m 100

3 0

3 years ago