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34kurt
3 years ago
5

A car weighs 1323 N. what is its mass?

Physics
2 answers:
Shalnov [3]3 years ago
6 0
If the car is on the moon, its mass is about 817 kg.

If it's on the Earth, its mass is about 135 kg.
vesna_86 [32]3 years ago
6 0

Answer:

Mass of the car, m = 135 kg

Explanation:

The weight of the car is 1323 N. Let m is its mass. The relation between the mass and weight comes form Newton's second law of motion. We know that the weight of an object is the force that is exerted due to acceleration due to gravity.

The mathematical form of weight of an object is given by :

W = mg

g is the acceleration due to gravity

m=\dfrac{W}{g}

m=\dfrac{1323\ N}{9.8\ m/s^2}

m = 135 kg

So, the mass of the car is 135 kg. Hence, this is the required solution.

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Question 1
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The distance covered is simply the length of the entire trip, which is 12m + 16m, or 28m.

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3 years ago
If a change in speed “Δv” occurs and the mass starts at rest, would the change in speed also equal the final speed of the mass?
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3 0
3 years ago
A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa
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Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

\frac{C_2}{C_1} = \frac{2.3}{1.15}

a ) when charge remains constant

energy = \frac{q^2}{2C}

q is charge and C is capacity

energy stored initially E₁= \frac{q^2}{2C_1}

energy stored finally E₂ = \frac{q^2}{2C_2}

\frac{E_1}{E_2} = \frac{C_2}{C_1} = \frac{2.3}{1.15}

E_2 = \frac{1.15}{2.3 } \times E_1

= \frac{1.15}{2.3 } \times 8.38

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

\frac{E_2}{E_1} = \frac{C_2}{C_1}

\frac{E_2}{8.38} = \frac{2.3}{1.15}

E_2 = 16.76 .

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3 years ago
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