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34kurt
3 years ago
5

A car weighs 1323 N. what is its mass?

Physics
2 answers:
Shalnov [3]3 years ago
6 0
If the car is on the moon, its mass is about 817 kg.

If it's on the Earth, its mass is about 135 kg.
vesna_86 [32]3 years ago
6 0

Answer:

Mass of the car, m = 135 kg

Explanation:

The weight of the car is 1323 N. Let m is its mass. The relation between the mass and weight comes form Newton's second law of motion. We know that the weight of an object is the force that is exerted due to acceleration due to gravity.

The mathematical form of weight of an object is given by :

W = mg

g is the acceleration due to gravity

m=\dfrac{W}{g}

m=\dfrac{1323\ N}{9.8\ m/s^2}

m = 135 kg

So, the mass of the car is 135 kg. Hence, this is the required solution.

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On the way home from school, Taylor's car runs out of gas. He has to walk 25m north and 10m west in order to reach the nearest g
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Answer:

<em>The distance is 35 m and the magnitude of the displacement is 26.93 m</em>

Explanation:

<u>Displacement  and Distance</u>

These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is calculated independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.

Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:

d = 25 m + 10 m = 35 m

To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.

The magnitude of the displacement is the distance from (0,0) to (-10,25):

D=\sqrt{(25-0)^2+(-10-0)^2}

D=\sqrt{625+100}=\sqrt{725}

D = 26.93 m

The distance is 35 m and the magnitude of the displacement is 26.93 m

8 0
3 years ago
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
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