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4 years ago

9

Please hurry need ASAP!!! When a pendulum swings, at which point is kinetic energy highest?

1 answer:

Naddik [55]4 years ago

5 0

Answer:

5/1

Explanation:

Kinetic energy is energy from a moving object and if a pendulum is at the highest point it will go faster.

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The internal energy of a system increases by 36 joules. The system does work using 17 joules. What amount of heat was added to t

Ray Of Light [21]

General internal energy expression:

Uf = (Ui-W) + Q

Where Uf = Final internal energy, Ui = Initial internal energy, W = Work done, Q = Heat added

But,
Uf -Ui = ΔU = 36 J, W = 17 J. Then,
ΔU = -W +Q => Q = ΔU+W = 36+17 = 53 J

Therefore, heat added to the system is 53 Joules

8 0

4 years ago

Read 2 more answers

A straight wire of length 0.62 m carries a conventional current of 0.7 amperes. What is the magnitude of the magnetic field made

anyanavicka [17]

Answer:

Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T

Explanation:

Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :

$B=\frac{\mu_{0}I }{2\pi R }\times\frac{L}{\sqrt{L^{2}+R^{2} } }$ ......(1)

Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.

In this problem,

Current, I = 0.7 A

Length of wire, L = 0.62 m

Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m

Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m

Substitute these values in equation (1).

$B=\frac{4\pi\times10^{-7}\times 0.7 }{2\pi \times0.02 }\times\frac{0.62}{\sqrt{(0.62)^{2}+(0.02) ^{2} } }$

B = 6.99 x 10⁻⁶ T

3 0

3 years ago

An unknown mineral is scratched by a penny. It must _____.

Tanya [424]

The answer is a I think

8 0

3 years ago

Read 2 more answers

The north and south poles of a magnetic field produced by an electromagnet will switch when the direction of the BLANK changes.

joja [24]

The north and south poles of a magnetic field produced by an electromagnet will switch when the direction of the Current changes.

8 0

4 years ago

A 38.2 kg wagon is towed up a hill inclined at 17.5 ◦ with respect to the horizontal. The tow rope is parallel to the incline an

Tema [17]

Answer:

v = 8.57 m/s

Explanation:

As we know that the wagon is pulled up by string system

So the net force on the wagon along the inclined is due to tension in the rope and component of weight along the inclined plane

So as per work energy theorem we know that

work done by tension force + work done by force of gravity = change in kinetic energy

$F_t . d - (mgsin\theta)(d) = \frac{1}{2}mv^2 - 0$

so we have

$F_t = 129 N$

$\theta = 17.5^o$

m = 38.2 kg

d = 85.4 m

so now we have

$129(85.4) - (38.2)9.8sin17.5 (85.4) = \frac{1}{2}(38.2) v^2$

$v = 8.57 m/s$

7 0

3 years ago