Answer: 28.5 square units.
Step-by-step explanation: Separate the figure into a rectangle and a triangle. Count the length and width of the rectangle. The length of the rectangle is 8 units and the width is 3 units. To find the area use the formula l*w. 8*3=24.
Next find the area of the triangle section. The triangle is 3 units tall and 3 units wide. To find the area use the formula 1/2(l*w). 3*3=9. 9/2=4.5.
Finally add the areas of the rectangular section and the triangular section. 24+4.5=28.5.
Answer:
reflection over the x-axis and shifted 7 units down
For this case we must follow the steps below:
step 1:
We place each of the given points on a coordinate axis
Step 2:
We join the AC points (represented by the orange line)
We join the BD points (represented by the blue line)
It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.
In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: 
In this case, the slope of the orange line is
and that of the blue line is 
Then
, it is verified that they are perpendicular.
Thus, the conclusion is that ABCD is a rhombus and AC is perpendicular to BD.
Answer:
See attached image
Option D
Answer:
15%
Step-by-step explanation:
The first step is to find the loss
Cost price -selling price
37000-31450
= 5,550
The loss percent can be calculated as follows
= loss/cost price × 100
= 5550/37000 × 100
= 0.15×100
= 15%
Hence the loss percent is 15%
Answer:
0.1994 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 166 pounds
Standard Deviation, σ = 5.3 pounds
Sample size, n = 20
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P(sample of 20 boxers is more than 167 pounds)
Calculation the value from standard normal z table, we have,
0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds