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Alona [7]
3 years ago
11

Make the smallest

Computers and Technology
1 answer:
seraphim [82]3 years ago
3 0

Answer:

<em>Whole Numbers:</em>

0000 0001 (Binary) --> 1 (Decimal)

<em>Real Numbers:</em>

0000 0001 (Binary) -->  0.00390635 (Decimal)

Explanation:

In general, the smallest nonzero number that can be displayed in binary that is a whole number is 1.  Consider that as you increase by 1 in the binary system starting from 0, you will have the following:

0000 0000 == 0

0000 0001 == 1 (Smallest nonzero)

0000 0010 == 2

0000 0011 == 3

... etc.

Notice the smallest value here is decimal 1.  With this in mind, you will need to "program" you Flippy Do Pro to display this value.  Alternatively, if you consider decimal numbers in binary with the Flippy Do Pro, you can have even smaller nonzero numbers.  Depending on where you decide to place the decimal, you can even have smaller nonzero values.

Let's assume that you say this is a fractional representation of binary on the Flippy Do Pro.  Then, you will say your decimal is infront of the display of the Flippy Do Pro, hence index 9 (which is not displayed).  From here, you will simply say the following:

0000 0000 == 0.0

0000 0001 == 0.00390635 (Smallest nonzero)

0000 0010 == 0.0078125

0000 0100 == 0.015625

... etc.

Note, in binary, as you move the value of 1 to the right of the decimal, you are doing (1 / 2^n), where n is the index value to the right of the decimal.

Hence, depending on if you are to consider just whole numbers or real numbers, the smallest value displayed can be different even though the number being displayed is still 0000 0001.

Cheers.

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5- NA

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Explanation:

1 - Select the slide you want to move

it allows us to select the slide which we want to move by just clicking left mouse button

2- Hold down the mouse button

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Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

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Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

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4 years ago
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