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Lelechka [254]
3 years ago
10

90 points please help question is in picture

Mathematics
2 answers:
slavikrds [6]3 years ago
6 0

Answer:

it should be 45%

denis-greek [22]3 years ago
5 0

Answer:

The probability is 45%

Step-by-step explanation:

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A shirt costs $5 less than a sweater. Together they cost<br> $25. How much does the sweater cost?
Aleksandr-060686 [28]

Answer:

Shirt: $7.5

Sweater: $17.5

Step-by-step explanation:

25/2=12.5

Shirt is 5 less than Sweater

12.5-5=7.5

Add 5 to sweater cost

12.5+5=17.5

Shirt=7.5 Sweater=17.5

17.5+7.5=25

6 0
3 years ago
PLEASE HELP. WORTH 50 PINTS IF CORRECT. A gate casts a shadow that is 5 feet long. A nearby cactus is 9 feet tall and casts a sh
brilliants [131]

Answer:

The height of the cactus is three times the height of the gate

The gate is 3 feet tall

3 0
3 years ago
Read 2 more answers
What is the cost if a $1,200 washing machine after a discount if 1/5 the original price
Fantom [35]
1/5 (or 20%) of $1,200 is $240
$1,200 - $240 = $960
The cost of a $1,200 washing machine after a discount of 1/5 (20%) is $960
3 0
3 years ago
Evaluate the following expression:
grigory [225]

Answer:

5.25

Step-by-step explanation:

7 0
3 years ago
You are at a European beach with 60 other visitors. 36 of them speak English. If you randomly meet two people on the beach, what
Kaylis [27]

Answer:

Assuming I'm one of the 36 English speakers and the other 24 speak Spanish for illustration purposes.  The problem can be modeled as 59 marbles with 35 E and 24 S marbles as N = 59 possible outcomes = n(E) + n(S) = 35 + 24.

So I reach into the pile of marbles (on the beach) and the probability that it's p(E) = n(E)/N = 35/59 = 0.593220339 when I meet the one person. ANS

I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three.  This one is p(E >= 1|4 attempts).  We can trace out a probability tree to identify those branches that contain at least one E event.  So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =  

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619   ANS.  In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

00

Step-by-step explanation:

3 0
2 years ago
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