Answer:
There are
Explanation:
In this problem, we need to find the number of molecules in mol of
.
The molar mass of is
No of moles = mass/molar mass
We can find mass from above formula.
Also,
No of moles = no of molecules/Avogadro number
Hence, there are
<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of = 480.1 g
Molar mass of = 84 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
4 moles of produces 2 moles of chromium (III) oxide
So, 5.72 moles of will produce =
of chromium (III) oxide
Now, calculating the mass of chromium (III) oxide from equation 1, we get:
Molar mass of chromium (III) oxide = 152 g/mol
Moles of chromium (III) oxide = 2.86 moles
Putting values in equation 1, we get:
To calculate the percentage yield of chromium (III) oxide, we use the equation:
Experimental yield of chromium (III) oxide = 402.4 g
Theoretical yield of chromium (III) oxide = 434.72 g
Putting values in above equation, we get:
Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.