Answer:
Atoms start out with the same number of negative charges (electrons), and positive charges (protons). ... Conversely, adding electrons to an atom would result in a negative ion. If you do this enough times, you can make an object positive or negative. Friction is one of the ways to separate charge.
Explanation:
Answer:
(a) 282 kJ
(b) 67.4 Calories
Explanation:
(a) The molar enthalpy, ΔH = −2802.5 kJ/mol, means that the heat produced by the reaction is 2802.5 kJ per mol of glucose.
We can multiply the enthalpy by the number of moles of glucose to get the heat produced by the metabolism. Grams of glucose will be converted to moles using the molar mass of glucose (180.156 g/mol):
(18.1 g)(mol/180.156g)(2802.5 kJ/mol) = 282 kJ
(b) Using the result we obtained above, kJ will be converted to Calories using the conversion factor of 4.184J = 1 cal. Calorie with a capital C is the same as a kilocalorie.
(282 kJ)(1 cal/4.184J) = 67.4 kcal = 67.4 Calories
Spotted Lantern: Destroying our trees
Fishers: Brought to lower numbers of certain species, but have dramatically lowered other species.
Zebra Mussels: Clog pipes
Emerald Ash Borer: Ruins ash trees that provide us with durable wood.
Answer : The water's temperature change will be, 
Explanation : Given,
Density of water = 0.998 g/mL
Volume of water = 
(conversion used : 1 L = 1000 mL)
Specific heat of water = 
Heat absorbed = 
(conversion used : 1 kJ = 1000 J)
First we have to determine the mass of water.


Now we have to calculate the change in temperature of water.
Formula used :

where,
Q = heat absorbed by water
m = mass of water
= specific heat of water
= change in temperature
Now put all the given value in the above formula, we get:


Therefore, the water's temperature change will be, 
Answer:
H2-1
H2+-1/2
H22- zero
Explanation:
Bond order= Bonding electrons-antibonding electrons/2
In H2, there are two bonding electrons and no antibonding electrons. In H2+ there is only one bonding electron and no antibonding electron while in H22- there are two bonding and two antibonding electrons respectively.