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enyata [817]
2 years ago
9

How many grams of water will be produced when 14.9 L of H2 reacts according to the following equation?

Chemistry
1 answer:
mezya [45]2 years ago
6 0

Answer:

2moles of H2 will react with 1mole of O2 to form 1 mole of water

If H2 is 14.9

O2 will be 14.9×2=29.8

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ivann1987 [24]
Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms 

<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

<span>Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles </span>

<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

<span>Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr</span>
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its a redox reaction.

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Stolb23 [73]
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Answer: 0.450 M H2SO4

Explanation:

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= 1.35 moles/3.00 L

= 0.450 M H2SO4

Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.

Hope this helps!

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