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jekas [21]
3 years ago
8

Find the amount in kJ of heat exchanged by the combustion of 61.9 g of ethane (C2H6(8) given that the molar enthalpy of combusti

on of ethane is -1,451 kJ/mol. 3
or more sig figs
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

2994 kJ

Explanation:

When one mol of ethane (C₂H₆) is combusted, 1451 kJ of heat is exchanged.

First we convert 61.9 g of C₂H₆ into moles, using its molar mass:

  • 61.9 g ÷ 30 g/mol = 2.06 mol C₂H₆

Finally we <u>calculate how much heat is exchanged by the combustion of 2.06 moles of C₂H₆</u>:

  • 2.06 mol * 1451 kJ/mol = 2994 kJ
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What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? E
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Name the following compound: 2-ethyl-4-methylheptene 3,5-dimethyl-2-octene 2-ethyl-4-methylheptane 3-methyl-5-propyl-2-hexene
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Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?
xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>

<u />

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when  formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>

It can be written as

CH_{2} O + CH_{3} COCH_{3} → HOCH_{2} -CH_{2} -CO-CH_{3}

When it will be heated then it gives methyl vinyl ketones.

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So, the pair of reactants will be formaldehyde and acetone

To know more about aldol condensation

brainly.com/question/9415260

#SPJ4

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