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sdas [7]
4 years ago
14

WILL GIVE BRAINLIEST!!!!! PLS ANSWER ASAP!!!!!

Mathematics
2 answers:
Margarita [4]4 years ago
6 0

The answer is <em>A) (–1, 0)</em> and <em>B) (–1, –5)</em> on Edge 2020

hram777 [196]4 years ago
4 0

Answer:

The coordinates of the image trapezoid are

A"(-4,5), B''(-1,5), C''(0,3), D''(-5,3)

The pre-image was first reflected in the line y=x, so the mapping will be

The resulting coordinates were then translated 4 units right;

For A''(-4,5), y+4=-4 and x=5

This means y=-8, x=5

Hence A(5,-8)

For B''(-1,5), y+4=-1, and x=5.

This means y=-5 and x=5

B(5,-5)

For C''(0,3), C(3,-4)

For D''(-5,3), D(3,-9)

Step-by-step explanation:

there u  go

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Write an equation that expresses the following relationship. p varies jointly with the square of d and the cube of u In your equ
Veronika [31]

Answer:

p= kd^{2}u^{3}

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

p= kd^{2}u^{3}

5 0
4 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
HELP ME ANSWER PART C‼️
wel

Answer:

PART C OF WHAT I CAN HELP IF YOU TELL ME

8 0
4 years ago
Read 2 more answers
If you want to buy an item in a store that costs $50 and is on sale for 10% off, then how much would the item actually cost you
SCORPION-xisa [38]

Answer: The item would be 45 dollars.

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Consider this system of linear equations:
Hatshy [7]
I believe the answer is D. because -12 + -1 equal -13 
5 0
3 years ago
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