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2 years ago

___ may be rinsed over materials to was off explosive residue. A) water B) bleach C) acid D) acetone

Chemistry

2 answers:

Sergio [31]2 years ago

4 0

Answer: D.

Explanation: D. Acetone, Acetone may be rinsed over materials to wash off the explosive residue.

Hope this helps :)

inysia [295]2 years ago

3 0

D ) acetone bc the others don’t make the cut /.

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What is the reaction between an acid and a base

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They create salt when put together

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3 years ago

What element has 28 electrons when electrically neutral

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Answer:

nickel

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Explanation:

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2 years ago

2. Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)

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Using mole calculations you can find that 10g of Al produces 24.3g of Fe under the conditions described

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2 years ago

Which element will only gain one electron during a chemical reaction?

Gelneren [198K]

Halogens

Explanation:

Halogens are a group of non-metals located in the seventh group on the periodic table. The will only gain one electron during a chemical reaction.

Halogens have a seven electrons in their outermost shell.
To complete the number of electrons in this shell, they need to gain an additional electron.
One more electron makes the halogen similar to the corresponding noble gas which is very stable.
Halogens are very reactive groups of elements and are highly electronegative.
They have a high affinity for electrons.
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7 0

2 years ago

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)

Paha777 [63]

<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
Multiply/Divide: $\displaystyle 16.6685 \ g \ H_2O$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

6 0

2 years ago