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bonufazy [111]
3 years ago
9

Indicate the oxidation number of oxygen for each compound in the following reaction: 2H2O2(aq)→ 2H2O(l) O2(g) Select the choice

that gives the oxidation numbers of H2O2, H2O(l), and O2(g), respectively.
Select the choice that gives the oxidation numbers of , , and , respectively. −1, −2, 0 −1, 0, −2 0, −2, −1 −2, −1, 0
Chemistry
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

2H2O2(aq)→ 2H2O(l) O2(g) : The oxidation number of oxygen for each compound is -1, -2, 0

Explanation:

In peroxides the oxidation state of oxygen is -1, since one oxygen bonds to the other oxygen and a hydrogen and the bound oxygen captures the electron of the remaining hydrogen. Through a scheme would be

H --- O --- O --- H

We remember that oxygen needs two electrons to get to have the configuration of the nearest noble gas (Lewis octet rule). In Peroxides, the oxygen is linked by covalent bonds. If we take it strictly, peroxide is a grouping of two oxygen, having the whole valence -2. which is why it is usually said that it is when oxygen has a valence -1

As we said the oxidation state is -2, the one that appears in the water molecule, since Hydrogen acts with valence +1 and it is 2 atoms that give up electrons to compensate for oxygen.

In the O2 it acts with valence 0 since we talk about gas in its elementary state. All diatomic molecules in their elemental state, generally gases or metals in solid state, act with a valence of 0.

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When a sample of rust was mixed with acid, the rust changed into two simpler substances: W and Z. The substances W and Z could n
julia-pushkina [17]

here can be a number of chemical processes by which a compounds can be broken down into simpler substances. The most common and wide-spread of such processes is Catabolism. Along with anabolism, catabolism make up the metabolism process for living organisms. In catabolism, complex chemical molecules (such as proteins, polysaccharides, etc.) are broken down into simpler molecules (such as amino acids, monosaccharides, etc.). This is often accompanied by release of energy in the form of ATP (adenosine triphosphate) molecules and intermediate metabolites (which can be used by the organism in the anabolic processes). The energy thus generated is used for operation and maintenance of cells (and consequently, the body).  

Other processes that break down chemical substances into simpler substances, include depolymerization, decomposition, etc.

Hope this helps.

6 0
3 years ago
Read 2 more answers
aluminum has a specific heat of 0.897 j/g°C. how much heat is needed to raise the temperature of a 79 gram piece of aluminum 28°
frutty [35]

Answer:

Approximately 2000 J.

General Formulas and Concepts:

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>c</em> = 0.897 J/g °C

[Given] <em>m</em> = 79 g

[Given] ΔT = 28°C

[Solve] <em>q</em>

<em />

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                             q = (79 g)(0.897 J/g °C)(28 °C)
  2. Multiply [Cancel out units]:                                                                               q = (70.863 J/°C)(28 °C)
  3. Multiply [Cancel out units]:                                                                               q = 1984.16 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

1984.16 J ≈ 2000 J

6 0
3 years ago
A car traveling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop in 7.5 seconds? What is the cars acc
Marianna [84]

Answer:

The acceleration is: 4m/s^2

Explanation:

Given

u = 30.0m/s --- The initial velocity

t = 7.5s --- time

v = 0m/s -- The final velocity

Required

Determine the acceleration

To do this, we make use of the first equation of motion

v = u - at

We used negative because the car was coming to stop.

This gives:

0 = 30 - 7.5 * a

0 = 30 - 7.5a

Collect like terms

7.5a = 30

Solve for a

a = \frac{30}{7.5}

a = 4m/s^2

6 0
3 years ago
True or false?
sertanlavr [38]
The answers are :
1 - F
2- T
5 0
2 years ago
Read 2 more answers
Calculate the density of an object with a mass of 30g and volume of 6cm^3
Kipish [7]
Density = Mass ÷ Volume

D= 30g ÷ 6 cm^3

D= 5 g/dm^3

3 0
3 years ago
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