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Mice21 [21]
3 years ago
5

My test is tomorrow and I'm confused about how to solve these. pls halp

Chemistry
1 answer:
Stels [109]3 years ago
5 0

Answer:

Explanation:

  1. <em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em><em><u> </u></em>
  2. <em><u>BCAZ</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em>
  3. <em><u>And</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em>
  4. <em><u /></em><em><u /></em><em><u /></em><em><u /></em>
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Is filtration physical or chemical
Lesechka [4]

Answer:

physical

Explanation:

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8 0
4 years ago
Based on the molar masses, how can you tell that an equation is balanced?
Ilya [14]
When you work with molar mass, you solve for the quantity of ''Moles'' within the substance by converting Mass. The way you can tell the equation is balanced would be by knowing whether the moles were equivalent on both sides or not. Therefore, if they are equal, it is balanced considering you have the same amount of moles on each side of the equation.
7 0
4 years ago
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How many total ions are present in 347g of cacl2?
vladimir1956 [14]

In 1 mole of CaCl_{2}, there are 3 moles of ions, 1 mole of Ca^{2+} and 2 mole of Cl^{-1}.

CaCl_{2}\rightarrow Ca^{2+}+2Cl^{-}

Molar mass of CaCl_{2} is 110.98 g/mol. Calculating number of moles from given mass as follows:

n=\frac{m}{M}=\frac{347 g}{110.98 g/mol}=3.12 mol

Thus, number of moles of ions will be 3\times 3.12 mol=9.38 mol.

Since, 1 mole of any substance has 6.023\times 10^{23} units of that substance where 6.023\times 10^{23}  is Avogadro's number.

Thus, 9.38 mol of ions will have 9.38\times 6.023\times 10^{23}=5.65\times 10^{24} number of ions.

Therefore, total number of ions in 347 g of CaCl_{2} is  5.65\times 10^{24}.


8 0
3 years ago
Why are animal vaccinated?
juin [17]

Answer:

to go against dangerous viral and bacteria

Explanation:

5 0
3 years ago
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