1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
QveST [7]
3 years ago
7

Four oranges were placed in a series circuit. Approximately what voltage did this produce?

Chemistry
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

Four times the original amount if only one orange was used

Explanation:

We can assume that the oranges all have equal voltages. Connecting them in series will have an increasing effect on the voltage delivered. In our case, this will produce 4 times the voltage of the circuit when only one orange is used.

Whenever simple cells are connected in series, the voltages of the individual cells are added up to form the voltage of the whole circuit.

Let us assume that the voltage of each of the oranges is approximately 0.9 volts. The Voltage produced when the 4 oranges are joined in series is 0.9 + 0.9 + 0.9 + 0.9 = 3.6 volts

You might be interested in
which person possessed the expeirence and to be commander in chief and continental army, in John Adams opinion?
sasho [114]
George Washington is your answer


Hope this helps!
6 0
3 years ago
57. The orbitals of an atom are distinguished from each other on the basis of their size, shape, and orientation in
Scilla [17]
False they are distinguished by probability
6 0
3 years ago
Read 2 more answers
The density of benzene is 0.879g/mL. The volume (with 1 decimal) of 131.9g sample of benzene is how many mL?
timurjin [86]

Answer:

150.1 mL

Explanation:

Step 1: Given data

  • Density of benzene (ρ): 0.879 g/mL
  • Mass of the sample of benzene (m): 131.9 g
  • Volume of the sample of benzene (V): ?

Step 2: Calculate the volume of the sample of benzene

Density is an intrinsic property. It is equal to the quotient between the mass and the volume of the sample of benzene.

ρ = m/V

V = m/ρ

V = 131.9 g/(0.879 g/mL)

V = 150.1 mL

5 0
3 years ago
A mixture of helium and methane gases, at a total pressure of 821 mm Hg, contains 0.723 grams of helium and 3.43 grams of methan
Nookie1986 [14]

<u>Answer:</u>

<u>For 1:</u> The partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

<u>For 2:</u> The mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For helium:</u>

Given mass of helium = 0.723 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{0.723g}{4g/mol}=0.181mol

  • <u>For methane gas:</u>

Given mass of methane gas = 3.43 g

Molar mass of methane gas = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane gas}=\frac{3.43g}{16g/mol}=0.214mol

To calculate the mole fraction , we use the equation:

\chi_A=\frac{n_A}{n_A+n_B}     .......(2)

To calculate the partial pressure of gas, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}       ......(3)

  • <u>For Helium gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{He}=\frac{0.181}{0.181+0.214}=0.458

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{He}=0.458

Putting values in equation 3, we get:

p_{He}=0.458\times 821mmHg=376mmHg

  • <u>For Methane gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{CH_4}=\frac{0.214}{0.181+0.214}=0.542

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{CH_4}=0.542

Putting values in equation 3, we get:

p_{CH_4}=0.542\times 821mmHg=445mmHg

Hence, the partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

  • <u>For 2:</u>

We are given:

Partial pressure of nitrogen gas = 363 mmHg

Partial pressure of carbon dioxide gas = 564 mmHg

Total pressure = (363 + 564) mmHg = 927 mmHg

Calculating the mole fraction of the gases by using equation 3:

<u>For nitrogen gas:</u>

363=\chi_{N_2}\times 927\\\\\chi_{N_2}=\frac{363}{927}=0.392

<u>For carbon dioxide gas:</u>

564=\chi_{CO_2}\times 927\\\\\chi_{CO_2}=\frac{564}{927}=0.608

Hence, the mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

6 0
3 years ago
What process is required for minerals to crystallize from magma
OleMash [197]

Answer:

Chemical differentiation

Explanation:

The process by which minerals crystallize out of magma is termed chemical differentiation. Some times, it is referred to as magmatic differentiation.

  • Minerals have different properties and at certain environment, it comfortable for the settle out of magma.
  • Some minerals can crystallize out at very high temperature.
  • Some will form at medium temperature whereas, some are low temperature minerals.
  • Based on the properties of the minerals in a melt, a minerals will differentiate at various temperature and pressure regimes.
5 0
3 years ago
Other questions:
  • What are atoms made of
    8·2 answers
  • What are the characteristics shapes of s p and d orbitals
    11·1 answer
  • A chemical reaction that absorbs energy in the form of heat is considered _____.
    5·1 answer
  • Water (3030 g ) is heated until it just begins to boil. If the water absorbs 5.49×105 J of heat in the process, what was the ini
    10·1 answer
  • If 22.5L of nitrogen at 748 mm Hg are compressed to 725mm Hg at constant temperature. What is the new volume?
    7·1 answer
  • What are the intermolecular forces present in Argon?
    13·1 answer
  • 6. The substance whose Lewis structure shows triple covalent bonds is
    7·1 answer
  • How many atoms in 3Mg(C7H5O3)2?<br><br> Mg:<br> C:<br> H:<br> O:
    9·1 answer
  • How many moles of lithium Sophie are in a simple with the number of atoms shown below?
    14·1 answer
  • What is the empirical formula
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!