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2 years ago

Four oranges were placed in a series circuit. Approximately what voltage did this produce?

Chemistry

1 answer:

vampirchik [111]2 years ago

3 0

Answer:

Four times the original amount if only one orange was used

Explanation:

We can assume that the oranges all have equal voltages. Connecting them in series will have an increasing effect on the voltage delivered. In our case, this will produce 4 times the voltage of the circuit when only one orange is used.

Whenever simple cells are connected in series, the voltages of the individual cells are added up to form the voltage of the whole circuit.

Let us assume that the voltage of each of the oranges is approximately 0.9 volts. The Voltage produced when the 4 oranges are joined in series is 0.9 + 0.9 + 0.9 + 0.9 = 3.6 volts

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What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$

$4.2 + log\frac{0.05}{0.045} = 4.245$

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

$pH = pKa + log\frac{base}{acid}$

$4.245 = 3.75 + log\frac{base}{acid}$

$log\frac{base}{acid} = 0.5$

$\frac{base}{acid} = 3.162$

Now we must solve the equation above. This will be done using the following values

$\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L$

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

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How many significant figures are in 120 miles?

balu736 [363]

2 significant zeros.

1 and 2 are the significant zeros.

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Which is one way that minerals crystallize from materials dissolved in water?

Andreyy89

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the second answer its science behind it

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Sunny_sXe [5.5K]

Answer:

Given: 800g S02 Unknown: ?g S

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(I've done this before and my teacher gave that answer)

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28. What is the heat of reaction for the forward reaction?

ValentinkaMS [17]

Answer:

Check Explanation

Explanation:

The Heat of reaction for the forward reaction is defined as the amount of heat given off or absorbed while the forward reaction is taking place. Mathematically, the heat of reaction for the forward reaction is given as the heat content/heat of formation/Enthalpies of the reaction's products minus the heat content/heat of formation/Enthalpies of the reaction's reactants.

ΔH°run = H°(products) - H°(reactants)

When the heat of reaction is negative, the reaction is said to be exothermic and when it is positive, the reaction is said to be endothermic.

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