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stealth61 [152]
3 years ago
15

What is angle B? Round the value to the nearest degree

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer: m\angle B=46\°

Step-by-step explanation:

For this exercise you need to use the Inverse Trigonometric function arccosine, which is defined as the inverse function of the cosine.

Then, to find an angle α, this is:

\alpha =arccos(\frac{adjacent}{hypotenuse})

In this case, you can identify that:

\alpha =m\angle B\\\\adjacent=AB=20\ cm\\\\hypotenuse=BC=29\ cm

Then, substituting values into \alpha =arccos(\frac{adjacent}{hypotenuse}) and evaluating, you get that the measure of the angle "B" to the nearest degree, is:

m\angle B=arccos(\frac{20\ cm}{29\ cm})\\\\m\angle B=46\°

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tatyana61 [14]
You would need one because you arent yet to 20 so it takes one tenth for example;

1.7 or 7/10

Thats my guess tho man if it is more complicated than that, SORRRYYYY
6 0
2 years ago
Given that 16 ounces equals 1 pound, how many ounces are in 12.4 pounds?
IceJOKER [234]

Answer:

198.4

Step-by-step explanation:

multiply the mass value by 16

4 0
2 years ago
Read 2 more answers
Show both decimal places (5.06).
lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0
1 year ago
Cost of a New Car From 1970 to 1990, the average cost of a new car, C
Lunna [17]

Answer:

In year 1986 the average  cost of car is  $12,000

Step-by-step explanation:

Cost function:

C = 30.5t² + 4192

Cost = $12,000

Find:

Year

Computation:

C = 30.5t² + 4192

12,000 = 30.5t² + 4192

t = 16 year

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Year 1970 + 16 year

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3 0
2 years ago
Round 98 inches to the nearest foot
weeeeeb [17]

Answer  8.17

Step-by-step explanation:

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98 \ 12

2.then round to the nearest tenth. 8.16 is rounded to  8.17

8 0
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