Answer:
Explanation:
¡Hola!
En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:
Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):
Quiere decir que las moles de N2(g) que se agregaron son:
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Chemical change, because the white powder heated the water and caused a thermal reaction, and possibly gas was produced due to bubbles.
Answer: Option (b) is the correct answer.
Explanation:
In liquid state, particles do have kinetic energy that helps in partially overcoming the intermolecular forces between the molecules. But still the particles are close together and they are able to slide past each other.
So, when we apply pressure on a liquid then its molecules partially gets compressed.
On the other hand, molecules of a solid are held together by strong intermolecular forces of attraction. Hence, they have definite shape and volume. As a result, solids do not get compressed.
In gases and plasma state of matter, molecules are gar away from each other. So, they are able to get completely compressed when a pressure is applied.
Thus, we can conclude that liquid is the state of matter which consists of particles that can be partially compressed.
Answer:
THE TEMPERATURE AT WHICH THE CHEMICAL REACTION IS BEING CONDUCTED.
Explanation:
The reaction rate constant is dependence on the temperature in which the reaction takes place. The rate of a reaction and the activation energy relationship is given by the Arrhenius equation with the rate constant as a function of temperature.
Mathematically, the rate constant is expressed as;
k(T) = Ae^-Ea/RT
where Ea is the activation energy, R is the gas constant, Ae is the pre-exponential factor and it is the frequency at which a reactant molecule collide with each other, T is the temperature.
Answer: B2H6 (g) + 3O2 (g) → B2O3 (s) + 3H2O (g) (ΔH = -2035 kJ/mol) 3H2O (g) → 3H2O (l) (ΔH = -132 kJ/mol) 3H2O (l) → 3H2 (g) + (3/2) O2 (g) (ΔH = 858 kJ/mol)
Explanation: ??
