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OLga [1]
3 years ago
12

The boiling point of an aqueous solution is 101.54 ∘C. What is the freezing point

Chemistry
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

101.54 .C.

Explanation:

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Leonard designed a parallel circuit to light two light bulbs. But his circuit doesn’t work. Which two items in the circuit must
klasskru [66]

Answer : When a parallel circuit is built the voltage across each of the components remains the same, also the total current passed is the equal to sum of the currents passing through each components in the circuits.


When 2 or more components are tried to be connected in parallel they maintain the same potential difference (in voltage) across their ends of the circuit.


The potential differences across the components are the observed to be same in magnitude, and they have identical polarities between them.


Then, this same voltage is applicable to all circuit components connected in parallel.


So, if each bulb is wired to the battery in a separate loop, the bulbs will be in parallel series.

3 0
3 years ago
The normal freezing point of water is 0.00 ⁰C. What is the freezing point of a solution containing450.0 mg of ethylene glycol (M
anyanavicka [17]

Answer:

Freezing T° of solution = - 8.98°C

Explanation:

We apply Freezing point depression to solve this problem, the colligative property that has this formula:

Freezing T° of pure solvent - Freezing T° of solution = Kf . m

Kf = 1.86°C/m, this is a constant which is unique for each solvent. In this case, we are using water

m = molality (moles of solute / 1kg of solvent)

We convert the mass of solvent from g to kg

1.5 g . 1kg/1000g = 0.0015 kg

We convert the mass of solute, to moles. Firstly we make this conversion, from mg to g → 450mg . 1g/1000mg = 0.450 g

0.450 g. 1mol / 62.07g = 7.25×10⁻³ moles

Molality → 7.25×10⁻³ mol / 0.0015 kg = 4.83 m

- Freezing T° of solution = 1.86°C /m . 4.83 m - Freezing T° of pure solvent

-Freezing T° of solution = 1.86°C /m . 4.83 m - 0°C

Freezing T° of solution = - 8.98°C

8 0
3 years ago
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Determine the enthalpy of solution for a solid with δh values as described in each scenario.
IrinaVladis [17]

Answer : To determine enthalpy of solution for a solid with δH values.


One can use the equation as H (reaction) = H (products) - H (reactants)


If δH values are known one can simply substitute them in the above equation and get the enthalpy of the required solution.

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3 years ago
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You did not link an image of it so I can’t see the rings.
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