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NemiM [27]
3 years ago
7

Which molecule is amphoteric?

Chemistry
2 answers:
frosja888 [35]3 years ago
4 0

Answer:

The answer is B

Explanation:

sergejj [24]3 years ago
4 0

Answer:

B. H2O

Explanation:

Well, for one example, we know that water is amphoteric... Examples: H2O can become H3O+ or OH-. HCO3- can become CO3^2- or H2CO3

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Please help me to answer this question.<br>i have to submit tomorrow.​
ratelena [41]

Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

4 0
3 years ago
What is the origin of the name for bismuth
Juliette [100K]
The name come from the German 'Bisemutum' a corruption of 'Weisse Masse' meaning white mass. 
6 0
3 years ago
The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
How many moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas?
sasho [114]

Answer:

2.5 mole O2 should react (2 * 2.5) = 5.0 mole H2 but there is 6.0 mole H2. H2 remain in excess. O2 is the limiting reactant. mole of H2O formed = 2 * 2.5 = 5.0 mole.

5 0
2 years ago
Predict the shape of the molecule.
balandron [24]

Answer:

B.) trigonal bipyramidal

Explanation:

A.) is incorrect. In octahedral molecules, the central atom is bonded to six other atoms.

B.) is correct. In trigonal bipyramidal structures, the central atom is bonded to five other atoms.

C.) is incorrect. In tetrahedral molecules, the central atom is bonded to four other atoms.

D.) is incorrect. There is not such thing as a pyramidal molecular shape. This term is most likely referring to the shape, trigonal pyramidal. However, this is still incorrect. In trigonal pyramidal molecules, the central atom is bonded to three other atoms and a lone pair of electrons.

7 0
1 year ago
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