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EleoNora [17]
3 years ago
11

What two factors most affect the pitch of the sounds made by a person's vocal cords? A. the volume and health of the person's lu

ngs B. the speed and volume of air pushed past the cords C. the temperature and humidity of the air outside D. the length and tension of the cord membranes
Chemistry
1 answer:
dusya [7]3 years ago
6 0

Answer:

The pitch of the sound a person makes is determined by several factors, including the size and tension of his or her vocal cords.

Explanation:

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Calculate the frequency of a wave with a wavelength of 5.62 x 1010 m. (first convert m to nm)
Readme [11.4K]

Answer:

f = 0.534×10⁻² Hz

Explanation:

Given data:

Frequency of wave= ?

Wavelength of wave = 5.62×10¹⁰ m

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3×10¹⁷ nm/s

λ  = 5.62×10¹⁰m×10⁹  nm/1 m = 5.62×10¹⁹ nm

Now we will put the values in formula.

3×10¹⁷ nm/s = 5.62×10¹⁹ nm ×  f

f = 3×10¹⁷ nm/s  / 5.62×10¹⁹ nm

f = 0.534×10⁻² s⁻¹   or

f = 0.534×10⁻² Hz

3 0
3 years ago
The electrons in an atom's outermost energy level are called: Electron dots. Quantum electrons. Valence electrons. Noble-gas ele
Flauer [41]

The valence electrons are located in an atom's outermost energy level

<h3>Further explanation  </h3>

In an atom, there are levels of energy in the shell and subshell  

This energy level is expressed in the form of electron configurations.  

Electrons fill the orbitals based on the Aufbau principle, namely the filling of electrons starts from the lowest energy level

  • Electron dots

Usually used in describing Lewis structures, placed around the element

  • Quantum electrons

Each orbital in an atom consists of 4 quantum numbers  : n, l, ml, ms

Each electron has a different quantum number and this conforms to Pauli's rule: no electrons have the same 4 quantum numbers

  • Valence electrons

Valence electrons are electrons used in a chemical bond , and  in an atom's outermost energy level

  • Noble-gas electrons

Noble gas has a stable electron configuration of 8 valence electrons which guides the formation of chemical bonds called the octet rule

3 0
3 years ago
As a maritime air mass moves across land, what happens to the air mass?
jasenka [17]

Answer:

the air mass will become colder

Explanation:

A maritime tropical air mass is moist and warm, while a continental polar air mass is dry and cold. ... When an air mass moves to a new region, it carries along its characteristic moisture and temperature. As the air moves over Earth's surface, the characteristics of the surface begin to change the air mass.

6 0
3 years ago
What is the formula for the stable binary ionic compound formed between Barium and Oxygen?
xeze [42]

Answer: a. BaO

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here element barium is having an oxidation state of +2 called as Ba^{2+} cation and O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral BaO

3 0
3 years ago
odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
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