Answer:
the statement is false for any value of x
Step-by-step explanation:
Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
I suck at math but I think he got one and half pounds
Answer:
sorry kid idontknow
Step-by-step explanation:
If MO bisects angle LMN:
6 x - 20 = 2 x + 36
6 x - 2 x = 36 + 20
4 x = 56
x = 56 : 4
x = 14
∠ LMN = 2 · ( 2 · 14 + 36 ) = 2 · ( 28 + 36 ) = 2 · 64 = 128
Answer : C ) x = 14, ∠ LMN = 128