If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.
The graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.
- A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5m
For more information on work done, visit
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The X and Y components of the force are 90.63 Newton and 42.26 Newton respectively.
<u>Given the following data:</u>
- Angle of inclination = 25°
To determine the X and Y components of the force:
<h3>The horizontal component (X) of a force:</h3>
Mathematically, the horizontal component of a force is given by this formula:
Fx = 90.63 Newton.
<h3>The vertical component (Y) of tensional force:</h3>
Mathematically, the vertical component of a force is given by this formula:
Fy = 42.26 Newton.
Read more on horizontal component here: brainly.com/question/4080400
<u>Answer</u>
3.7 Km south
<u>Explanation</u>
The definition of displacement is the distance traveled in a specific direction. It is the vector quantity. We add displacements like the way we add vectors.
Taking the direction towards North to be positive (+1.7 Km), the distance towards south would be negative (-5.4 Km).
Now lets add the two values.
(+1.7) + (-5.4) = 1.7 - 5.4
= - 3.7 Km But negative was towards south.
∴ Answer = 3.7 Km south.
The acceleration is 3 m/s per minute, or 0.05 m/s per second.
Answer:
okay sooo the weight is: 294 n
the normal force is 286 n
the acceleration is: -0.38 m/s²
