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VikaD [51]
4 years ago
5

PLEASE HELP ASAP

Physics
1 answer:
posledela4 years ago
4 0

the answer is that they both have a magnitude

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Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tig
Andru [333]
I=2.27 x 10 to the 3rd power A
5 0
3 years ago
A sound source is located somewhere along the x-axis. Experiments show that the same wave front simultaneously reaches listeners
galina1969 [7]

Answer:

Explanation:

As the source is situated on x - axis , it must be situated in between the two listeners .

So the x coordinate of source is

(-7 + 3 )/2

= - 2 m

The equation of the wave- front will be that o a circle having centre at (-2,0)

and radius = distance between -2 and 3 , that is 5 m

equation of circle

=( x+2 )² + y² = 25

It cuts y axis when x = 0

Putting x = 0

4 + y² = 25

y² = 21

y = + √21 , or - √21

7 0
4 years ago
Consider a river flowing toward a lake at an average velocity of 3 m/s. the river height is 90m above the lake. what is the tota
strojnjashka [21]

Kinetic energy per unit of mass is

K=\frac{v^{2} }{2}

Given, v=3m/s^{2}

Therefore,

K=\frac{(3^{2} m/s^{2} )^2}{2}

K=4.5 J/kg

Now potential energy per unit mass is

p=g\times h

Given, h=90 m

Therefore,

p= 9.8m/s^2 \times 90

p=882.9 J/kg

Thus, total mechanical energy of the river water per unit mass is

T=K+p=(4.5+882.9)J/kg

T=887.9 J/kg

OR

T=0.887 kJ/kg

6 0
3 years ago
Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
WINSTONCH [101]

Answer:

Explanation:

frequency of sound waves = 688 Hz

wavelength = 344 / 688 = .5 m

The problem is based on interference of sound waves

For the observer , path difference of sound waves reaching his ear

= 3.5 - 3.00

.5 m

= wavelength

Path difference is equal to wavelength so there will be constructive interference and hence louder sound will be heard by the listener than normal sound as sound waves interfere constructively.

6 0
4 years ago
Determine the energy lost, due to friction, as an 8000 N car that skids to a stop, if its initial velocity was 12 m/s.
chubhunter [2.5K]

Answer:

<em>58,800Joules</em>

Explanation:

The energy lost is equal to the workdone by the car as it skids.

Workdone = Force * Distance

Given

Force = 8000N

Get the distance using the equation of motion

v² = u² - 2gS

0² = 12² - 2(9.8)S

-12² =  - 2(9.8)S

-144 = -19.6S

S = 144/19.6

S = 7.35m

Calculate the required energy

Workdone = 8000 * 7.35

Workdone = 58,800Joules

<em>Hence the energy lost due to friction is 58,800Joules</em>

3 0
3 years ago
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