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A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntable’s angular velocity, in rpm, just after this event?
Answer:
w=50 rpm
Explanation:
Given data
The mass turntable M=2kg
Diameter of the turntable d=20 cm=0.2 m
Angular velocity ω=100 rpm= 100×(2π/60) =10.47 rad/s
Two blocks Mass m=500 g=0.5 kg
To find
Turntable angular velocity
Solution
We can find the angular velocity of the turntable as follow
Lets consider turntable to be disk shape and the blocks to be small as compared to turntable

where I is moment of inertia

Answer:
t = 1.10 h
Explanation:
For this exercise we must calculate the intensity that reaches the cell with the polarizers, for this we use Malus's law
I = I₀ cos² θ
Let's calculate
I = I₀ cos² 60
I = I₀ 0.907
This is the intensity that reaches the cell
To find time, use an inverse proportion rule or rule of three, the intensity Io in
t = I₀ / (0.907 I₀) 1 h
t = 1.10 h
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