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Maru [420]
3 years ago
15

A student conducts an experiment to test how the temperature of a ball affects its bounce height. The same ball is used for each

test, and the ball is dropped from the same height each time.
What is the independent variable?


the temperature of the ball

the type of ball

the drop height of the ball

the bounce height of the ball
Physics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

C or B

Explanation:

it said that the ball was dropped from the same height but answer C could also be the answer because it said that it was the same ball

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A 8.0 cm-diameter horizontal pipe gradually narrows to 4.5 cm. When water flows through this pipe at a certain rate, the gauge p
Fed [463]

Answer:

7.11x10^-3

Explanation:

We are to get the volume rate of flows

1/2pv1² + pl = 1/2pv2²

Such that A1V1 = A2V2

V1 = A2V2/A1

From the attachment I uploaded, we have a formula named equation 1 from which I have plugged in these values

P2 = 33000

P2 = 24000

P = 1000

r2 = 2.25

r1 = 4

When we put these values into the equation,

V2 = 4.47

A2V2 = pi(0.0225)²x4.47

= 7.7x19^-3m³/s

6 0
3 years ago
Communications satellites are placed in a circular orbit where they stay directly over a fixed point on the equator as the earth
zalisa [80]
Refer to the diagram shown below.

Given:
R = 6.37 x 10⁶ m, the radius of the earth
h = 3.58 x 10⁷ m, the height of the satellite above the earth's surface.
Therefore
R + h = 4.217 x 10⁷ m

In geosynchronous orbit, the period of rotation is 1 day.
Therefore the period is
T = (24 h)*(60 min/h)*(60 s/min) = 86400 s

The angular velocity is
ω = (2π rad)/(86400 s) = 7.2722 x 10⁻⁵ rad/s

Part (a)
The tangential speed is
v = (R+h)*ω
   = (4.217 x 10⁷ m)*(7.2722 x 10⁻⁵ rad/s) 
   = 3066.7 m/s
   = 3.067 km/s

Part (b)
The centripetal acceleration is
a = v²/(R+h)
   = (3066.7 m/s)²/(4.217 x 10⁷ m)
   = 0.223 m/s²

Answers:
(a) The speed is 3.067 km/s
(b) The acceleration is 0.223 m/s²

7 0
4 years ago
If the tire reaches a temperature of 48 ∘c, what fraction of the original air must be removed if the original pressure of 250 kp
andrey2020 [161]
Assuming air as ideal gas and amount of air in no of moles is known then by gas law,

PV= nRT

Pressure is constant

P* (change in volume) = nR* (change in temperature)
7 0
4 years ago
A car travelling at a constant speed of 70km/h passes a stationary police car. The police car immediately goes on the chase acce
Virty [35]

Answer:

18.24 seconds

Explanation:

First you convert the km/h to m/s, 70km/h=(175/9)m/s,85km/h=(425/18)m/s.

You know it took 10 seconds for the police to reach 85 km/h. Calculate the distance that the car is ahead of the police (175/9)*10=1750/9m. Then by divide 1750/9 with 425/18, you will get the value 8.24. Add the 10 seconds with the 8.24 you will get 18.24 sec which is the total time.

5 0
4 years ago
A sample of helium (He) occupies 8.0 liters at 1 atm and 20.0◦C. What pressure is necessary to change the volume to 1.0 liters a
nevsk [136]

Apply the combined gas law

PV/T = const.

P = pressure, V = volume, T = temperature, PV/T must stay constant.

Initial PVT values:

P = 1atm, V = 8.0L, T = 20.0°C = 293.15K

Final PVT values:

P = ?, V = 1.0L, T = 10.0°C = 283.15K

Set the PV/T expression for the initial and final PVT values equal to each other and solve for the final P:

1(8.0)/293.15 = P(1.0)/283.15

P = 7.7atm

7 0
4 years ago
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