1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tresset [83]
3 years ago
6

More buffer zones would be needed around a large protected area vs. several patches of protected area of equal square footage.

Physics
2 answers:
Fudgin [204]3 years ago
6 0

Your answer is it is True. Please no mean comments I'm new to brainly

Paha777 [63]3 years ago
6 0
False you need more buffer zones in smaller areas
You might be interested in
An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a
devlian [24]

Answer:

a

D =  1162.7 \  m

b

\beta =- 65.55^o

Explanation:

From the question we are told that

  The speed of the airplane is  u  =  92.3 \ m/s

   The  angle is  \theta = 51.1^o

    The altitude of the plane is  d =  532 \  m

Generally the y-component of the airplanes velocity is  

       u_y  =  v *  sin (\theta )

=>     u_y  =   92.3 *  sin ( 51.1 )

=>     u_y  =  71.83  \ m/s

Generally the displacement  traveled by the package in the vertical direction is

       d =  (u_y)t +  \frac{1}{2}(-g)t^2

=>       -532  = 71.83 t +  \frac{1}{2}(-9.8)t^2

Here the negative sign for the distance show that the direction is along the negative y-axis

 =>   4.9t^2 - 71.83t - 532 = 0

Solving this using quadratic formula we obtain that

    t =  20.06 \  s

Generally the x-component of the velocity is  

     u_x  =  u  *  cos (\theta)

=>    u_x  =   92.3  *  cos (51.1)

=>   u_x  =   57.96 \ m/s

Generally the distance travel in the horizontal  direction is    

     D =  u_x  *  t

=>   D =  57.96  *   20.06

=>    D =  1162.7 \  m

Generally the angle of the velocity vector relative to the ground is mathematically represented as

       \beta  =  tan ^{-1}[\frac{v_y}{v_x } ]

Here v_y is the final  velocity of the package along the vertical  axis and this is mathematically represented as  

     v_y  =  u_y  -   gt

=>  v_y  =  71.83  -    9.8 *  20.06

=>  v_y  =  -130.05 \  m/s  

and  v_x is the final  velocity of the package which is equivalent to the initial velocity u_x

So

       \beta  =  tan ^{-1}[-130.05}{57.96 } ]

       \beta =- 65.55^o

The negative direction show that it is moving towards the south east direction

   

6 0
3 years ago
What term describes the rate at which charge passes a point in a circuit
docker41 [41]
That's electric "current", usually described in 'Amperes'.

1 Ampere = 1 Coulomb per second ... "the rate at which
charge passes a point in the circuit".
8 0
3 years ago
Read 2 more answers
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position
Artist 52 [7]

Answer:

The distance of the first bright fringe is given as  Y_C = 1.22 *10^{-3}m

The distance of the second dark fringe from the central bright fringe is given as  Y_D = 0.00192 \ m

Explanation:

From the question we are told that

     The slit separation distance is  d = 1.15 mm = \frac{1.15}{1000} =0.00115 m

      The distance of the slit from the screen is  D = 3.23 m

        The wavelength is \lambda  = 633 nm

For constructive interference to occur the distance between the two slit is mathematically represented as

            Y_C  =\frac{m \lambda D}{d}

 Where m is the order of the fringe which has a value of 1 for first bright fringe

    Substituting  values

               Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}

                Y_C = 1.22 *10^{-3}m

For destructive  interference to occur the distance between the two slit is mathematically represented as

            Y_D  =  [n + \frac{1}{2} ] \frac{\lambda D}{d}

      m = 2

so the formula to get the dark fringe is n = \frac{1}{2} * 1

                                                                 n=1

 Now substituting values

                 Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}

                   Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}

                        Y_D = 0.00192 \ m

4 0
3 years ago
During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr
WINSTONCH [101]

Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

E = \frac{\Delta V}{d}

<u>Where:</u>

E: is electric field

ΔV: is the potential difference = 3.95 mV  

d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0
2 years ago
A driverless car collides head on with a stationary sign. The collision brings the car to a stop, but does not move the sign.
neonofarm [45]

Answer:

I'm sorry hindi ko po alam ung sagot sorry po

4 0
2 years ago
Read 2 more answers
Other questions:
  • Tiana jogs 1.5 km along a straight path and then turns and jogs 2.4 km in the opposite direction. She then turns back and jogs 0
    11·1 answer
  • 15. A machine must move an object 15.1 meters by exerting a 121 Newton force. If the machine
    6·1 answer
  • The Sun keeps all of the planets orbiting it because _____.
    5·2 answers
  • Add or subtract as indicated.
    6·1 answer
  • Give an example of a situation in which you would describe an object's position in
    9·1 answer
  • Consider a golf club hitting a golf ball that results in the following graph of force versus time on a 45 gram golf ball. If the
    12·1 answer
  • Suppose you are walking home from school. The distance from school to your is home is five kilometers. On foot,you can get home
    9·2 answers
  • An example of a constant acceleration is
    14·2 answers
  • Science help please!!!!!!!!!!!!!!!!!!!
    9·2 answers
  • A 1200 kg car is moving at 8 m/s when is strikes a barrier with an equivalent spring constant of 18,000 N/m. How far is the barr
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!