3 years ago

Please help asap I need this rn

Physics

1 answer:

den301095 [7]3 years ago

6 0

It’s the third one .

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An object with a velocity of

algol [13]

Answer:

v = 1.7 m/s

Explanation:

Given that,

Initial velocity of the object, u = 1 m/s

Acceleration of the object, a = 1 m/s²

We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

$v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s$

So, the final velocity of the object is 1.7 m/s.

4 0

3 years ago

turning on the television is a form of ___ energy that transforms into ___ energy and/or sound energy

MariettaO [177]

Electric energy into light energy and sound energy

8 0

2 years ago

Which would be the best example to demonstrate the principle of conservation of energy? A) a stone is crushed B) light bends aro

Daniel [21]

The answer is a pendulum swings back an forth.

6 0

3 years ago

Read 2 more answers

on the surface of theearth ,the weight of a boy is 400N but on a mountainpeak his weight is 360N,Calculatethe value of ''g' on t

andreyandreev [35.5K]

The value of g at sea level is 9.81 ms^-2.

The boy's mass is constant wherever he is in the universe but his weight will depend on the strength gravity where he is.

By proportion its value on the mountain peak is (360 /400) * 9.81

= 0.9 * 9.81 = 8.83 ms^-2 to nearest hundredth, (answer).

7 0

2 years ago

Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?

noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

$k = 9 * 10^9$

$q_1 = 2pC$

$q_2 = 4pC$

$r = 6cm = 0.06 m$

now by using the above equation we have

$F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}$

$F = 2 * 10^{-11} N$

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

3 0

2 years ago