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Maksim231197 [3]
3 years ago
10

Please help asap I need this rn

Physics
1 answer:
den301095 [7]3 years ago
6 0
It’s the third one .
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After our sun leaves the main sequence it will most likely
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Our Sun will probably become a red giant before collapsing into a dwarf star.
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A small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbank
Alenkasestr [34]

Answer:

(D) F/2

Explanation:

Since the circular section is unbanked, the centripedal acceleration acting on each of the cars is

a_s = \frac{v_s^2}{r} = \frac{(2v)^2}{r} = \frac{4v^2}{r}

a_l = \frac{v_l^2}{r} = \frac{v^2}{r}

Therefore the centripetal force on each car

F_s = m_sa_s = \frac{4mv^2}{r}

F_l = m_la_l = \frac{2mv^2}{r}

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So (D) F/2 is the correct answer

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3 years ago
A cart is rolling down a ramp. if the angle of the ramp is increased to make the ramp steeper the cart will​
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A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

\Delta m = 330000\,kg

b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

450000\,kg = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (550\,m^{2})\cdot (h-0.45\,m)

The final submersion height is:

h = 1.268\,m

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273 k hope this helps :)
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