Answer:
a ) = 381.48 J
b )= 84.25 cm
Explanation:
Kinetic energy of the runner
= 1/2 m v²
= .5 x 66 x 3.4²
= 381.48 J
The final kinetic energy of the runner is zero .
Loss of mechanical energy
= 381.48 J
This loss in mechanical energy is due to action of frictional force .
b )
Let s be the distance of slide
deceleration due to frictional force
= μmg/m
.7 x 66 x 9.8 / 66
a = - 6.86 m s⁻¹
v² = u² - 2 a s
0 = 3.4² - 2x6.86 s
s = 3.4² / 2x6.86
= .8425 m
84.25 cm
I believe it is Convection, then again I'm not in college.
Answer:
2 m/s
Explanation:
Parameters given:
Mass of first skateboard, m = 3 kg
Initial speed of first skateboard, u = 4 m/s
Mass of second skateboard, M = 1 kg
Initial speed of second skateboard, U = 0 m/s
Final speed of second skateboard, V = 6 m/s
Using the principle of the conservaton of momentum, the total initial momentum is equal to the total final momentum.
Momentum is the product of mass and velocity. This implies that:
m*u + M*U = m*v + M*V
(3*4) + (1*0) = (3*v) + (1*6)
12 + 0 = 3v + 6
=> 3v = 12 - 6
3v = 6
v = 6/3 = 2 m/s
The final speed of the 3 kg skateboard is 2 m/s
I’ll refer to electromagnetic radiation as EMR.
Visible light is a very small subset of EMR. Many other ranges like infrared, ultraviolet, or gamma must be detected by special equipment.
EMR is what makes up light, and as we know from any high school physics class, light exhibits both particle-like properties (photoelectric effect and Compton scattering) and wave-like properties (refraction, diffraction, double-slit & single-slit experiment).
EMR can travel without a medium, like the vast emptiness of space. It can also travel with a medium. It can transmit through various materials albeit at a slower speed, like water, earth’s atmosphere, glass etc.
The propagation speed of EMR in space is 3x10^8 m/s, which is a speed unattainable by any of our current means of transportation. I would say that’s quite fast.
Answer:
a) h = 14 m
b) h = 88 cm
c) f = 0.054 Hz
d) f = 0.13 Hz
Explanation:
a) T = 2π√(L/g)
L = T²g/4π²
L = (45/6)²(9.8) / 4π² = 13.963...
b) ½mv² = mgh
h = v²/2g
h = 4.15²/ (2(9.8)) = 0.87869
c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542
d) f = 6/45 = 0.13333...
