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Monica [59]
3 years ago
7

How does the steepness of the line on a speed graph relate to the objects speed

Physics
1 answer:
Likurg_2 [28]3 years ago
3 0
That depends on what is being graphed.

-- On a speed/time graph, the higher the speed, the higher the point on the line. 
A constant speed will be a horizontal piece of line.

-- On a distance/time graph, the higher the speed, the steeper the line is sloped.

-- On a temperature/time graph, the line on the graph is not related
to the object's speed at all.

-- etc.
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A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st
elena-14-01-66 [18.8K]

Answer:

The frequency of the piano string is <em>1059 Hz</em>.

Explanation:

The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.

As the piano string gets tightened, the frequency beat becomes 3 beats/second.

Therefore,

fb = fb = fpiano - ftuning fork\\ 3 Hz=fpiano-1056Hz\\ fpiano=1056Hz+3Hz\\ fpiano=1059Hz

6 0
3 years ago
Which of the following can lower the activation energy of a system?
exis [7]
Catalysts
a catalyst is something added to a reaction that speeds it up (or lowers the activation energy)

increasing the temp would speed up the whole reaction but not lower the activation energy
so B.
8 0
3 years ago
Field lines point straight out from all sides of an object. Which statement best describes the object?
Mashcka [7]
It is positively charged.
8 0
3 years ago
Read 2 more answers
(b) The cylinder shown in figure 2 is fitted with a freely sliding piston containing an ideal gas of mass 13g and volume 1.0×10⁴
nekit [7.7K]

Answer:

22600 cm³ (3 s.f.)

Explanation:

Please see the attached picture for the full solution.

6 0
2 years ago
2. Three super strong teenagers pull a heavy crate across the floor. Dion pulls with a force of 18.5 N towards 0°. Shirley pulls
kogti [31]

Answer:

A) The resultant force is 43.4 [N]

B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis

Explanation:

We need to make a sketch of the different forces acting on the heavy crate.

In the attached image we can see the forces and the sum of the vector with their respective angles.

Forces in the X-axis

Fdionx=18.5N\\\\Fshix=16.5*cos(30)=14.29N\\Fjoanx=19.5*cos(60)=9.75N\\\\Forcex= 18.5 + 14.29 + 9.75 = 42.54 N

Forces in the y-axis

FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]

Using the Pythagorean theorem

Tforce=\sqrt{(42.54)^{2} +(8.63)^{2} } \\\\Tforce= 43.4N

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.

8 0
3 years ago
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