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nordsb [41]
3 years ago
13

Show that (2, 1) is a solution of the system of equations.

Mathematics
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

x = 2

y = 1

Step-by-step explanation:

y = -x + 3

x + 3y = 5

x + 3(-x + 3) = 5

x - 3x + 9 = 5

-2x + 9 = 5

-2x = 5 - 9

-2x = -4

x = -4/-2

x = 2

y = –x + 3

y = -2 + 3

y = 1

pentagon [3]3 years ago
3 0
X+3y=5
Y=-x+3
X=2
Y=1
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ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
2 years ago
a. Solve x + 9 = x + 9. b. If you simplify an equation and get 0 = 0, what can you conclude about the solution(s) of the origina
Wittaler [7]
My friend told me the answer is 57
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2 years ago
The value of 8 in 56982 is how many times larger than the value of 8 in 156408
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Hope this helps x
3 0
3 years ago
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Please help asap 25 pts
Alchen [17]
The answer to you question is c
5 0
2 years ago
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I need help with this question. i dont seem to understand how to solve it
ioda
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