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inysia [295]
3 years ago
12

translate this sentence into an inequality. A cheetah can reach a speed of 70 mph. however, this speed can be maintained for no

more than 1,640 feet. A. d>1,640 B. d_<1,640 C. d<1,640 D. d_>1,640
Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0
<h2>Hello!</h2>

The answer is:

B. d\leq 1,640ft

<h2>Why?</h2>

From the statement we know that the cheetah can reach a speed of 70 mph, but it can be maintained for no more than 1,640 feet.

The expression "no more than" means that at least it can be reached but never exceeded, it involves that the distance can be less or equal than 1,640 feet but never more than that.

So, the correct option is:

B. d\leq 1,640ft

Have a nice day!

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I need help with this question
nikdorinn [45]
The area of each triangular face is
.. A = (1/2)*b*h
.. Aside = (1/2)*(6 cm)*(5 cm) = 15 cm^2

The area of the triangular base is
.. Abase = ((√3)/4)*s^2 = (√3)/4*(6 cm)^2 = 9√3 cm^2

The total surface area is the base area plus the area of the three sides.
.. Atotal = Abase + 3*Aside
.. = 9√3 cm^2 +3*15 cm^2
.. = (45 +9√3) cm^2
.. ≈ 60.6 cm^2


Actually, there's an error in the picture. The height of the side should be 4, and the length of the edge should be 5. Making that adjustment, the total area is 51.6 cm^2.

It is hard to tell what is intended. Not all answers are showing, so we can't "reverse-engineer" the problem from the answers.
7 0
3 years ago
in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
Find the area of the irregular figure. Round to the nearest hundredth
stepladder [879]

Answer:

total area = 100

Step-by-step explanation:

10 x 4 = 40

1/2 * 6 * 10 = 30 ( x 2 triangle) = 60

total area = 40 + 60

total area = 100

6 0
3 years ago
Which is a compsite number
andriy [413]

Answer:

a number yat has more than 2 multiples

8 0
3 years ago
What multiplication problem matches this addition problem?
tiny-mole [99]
6*7=42
It’s the answer I guess.
8 0
2 years ago
Read 2 more answers
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