Answer:
See explanation
Explanation:
This conversion must go through a sequence of steps as i have shown in the image attached to this answer.
The acetone is converted to propan-2-ol using LiAlH4, THF and acid. The propan-2-ol may be converted to propene by E2 elimination. Addition of HBr yields 2-bromo propane.
The Wurtz reaction converts 2-bromo propane to 2,3- dimethyl butane. This can be brominated in the presence of light to yield 3-bromo-2,3-dimethyl butane. Elimination of HBr using a base leads to the formation of the required product as shown.
Are produced 72 grams of water in this reaction.
<h3>Mole calculation</h3>
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
Finally, just find the number of grams of water using your molar mass:
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
Answer is: <span>mass of water is 6.07 kilograms.
</span>b(NaOH) = 1.35 m.
n(NaOH) = 8.20 mol.
b(NaOH) = n(NaOH) ÷ m(H₂O).
m(H₂O) = n(NaOH) ÷ b(NaOH).
m(H₂O) = 8.20 mol ÷ 1.35 mol/lg.
mm(H₂O) = 6.07 kg.
m - molality.
n - amount of substance.
