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3 years ago

Please help with correct answer for the one marked :)

Chemistry

1 answer:

ehidna [41]3 years ago

5 0

Answer:

Question 4 is not clear sorry you may send another picture please

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What is silicone used for

enot [183]

Answer:

sealants, adhesives, lubricants, medicine, cooking utensils, and thermal and electrical insulation

Explanation:

6 0

3 years ago

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the temperature of a balloon rises from 275 degrees k to 395 degrees k, what would the ending volume be if it started at 5 L

Airida [17]

<h3>Answer:</h3>

7.182K

<h3>Explanation:</h3>

From the question we are given;

Initial temperature, T1 = 275 K
Final temperature, T2 = 395 K
Initial volume, V1 = 5 L

We are required to calculate the final volume, V2

Charles's law is the law that relates the volume of a gas and its temperature.
It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
Therefore;

$\frac{V1}{T1}=\frac{V2}{T2}$

To calculate, V2 we rearrange the formula;

$V2=\frac{V1T2}{T1}$

$V2=\frac{(5L)(395K)}{275}$

$V2=7.182K$

Therefore, the ending volume will be 7.182K

8 0

4 years ago

Can someone help? Ill give brainliest!

-Dominant- [34]

Answer:

Explanation:

before the reaction you have N=2 and H=6 after the reaction you have N=2 and H=6 so yes it follows the law

7 0

3 years ago

A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.

amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = time passed by the sample = 60.0 min

a = let initial amount of the reactant = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

$k=\frac{2.303}{60.0}\log\frac{100g}{75g}$

$k=4.79\times 10^{-3}\text{ years}^{-1}$

Now we have to calculate the half-life of the compound.

$k=\frac{0.693}{t_{1/2}}$

$4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=144.676\text{ years}\approx 145\text{ years}$

Therefore, the half-life of the compound is, 145 years.

8 0

4 years ago

1) How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7g Fe? Show your work.

klasskru [66]

1.) is157.7 g
moles Fe = 209.7 g/ 55.847 g/mol=3.75
the ratio between Fe and CO is 2 : 3
moles CO = 3.75 x 3 /2 =5.63
mass CO = 5.63 mol x 28.01 g/mol=157.7 g

2.) is 1.06 moles
48.7/23 = 2.12 moles sodium
2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles 
1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen.

3.) is 91.8
8.3 moles H2S x (2 moles H2O / 2 moles H2S) = 8.3 moles H2O = theoretical amount produced. 8.3 moles H2O x (18.0 g H2O / 1 mole H2O) = 149 g H2O produced theoretically. % yield = (actual amount produced / theoretical amount) x 100 = (137.1 g / 149 g) x 100 = 91.8

6 0

3 years ago

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