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Bas_tet [7]
3 years ago
14

A gas evolved during the fermentation of sugar was collected at 22.5°C and 702 mmHg. After purification its volume was found to

be 25.0 L. How many moles of gas were collected?
A) 0.95 mol
B) 1.05 mol
C) 12.5 mol
D) 22.4 mol
E) 724 mol
Chemistry
1 answer:
miskamm [114]3 years ago
4 0

Answer:

A) 0.95 mol

Explanation:

We will assume the gas given off in the fermentation is an ideal gas because that allows us to use the ideal gas equation.

PV  = nRT

First let's convert all measurements to units that we can use

P = 702 mmHg * 1 atm/760 mmHg = 0.92368 atm

V = 25.0 L

R = 0.08206 L-atm/mol-K

T = 22.5 °C +273.15 = 295.65 K

PV  = nRT

0.92368 atm * 25.0 L = n * 0.08206 L-atm/mol-K * 295.65 K

                                  n = 0.9518 mol

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The weight of the body in the air is .... the weight of the submerged body
stira [4]

Answer:

the correct answer is option 'b': More than

Explanation:

The 2 situations are represented in the attached figures below

When an object is placed in air it is acted upon by force of gravity of earth which is measured as weight of the object.

While as when any object is submerged partially or completely in any fluid the fluid exerts a force in upward direction and this force is known as force of buoyancy and it's magnitude is given by Archimedes law as equal to the weight of the fluid that the body displaces, hence the effective force in the downward direction direction thus the apparent weight of the object in water decreases.

4 0
3 years ago
If the volume of a gas at 0.5 atm changes from 150 mL to 75 mL, what is the new pressure?
prisoha [69]

Answer:

<h2>1 atm</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2 =  \frac{0.5 \times 150}{75}  =  \frac{75}{75}  = 1 \\

We have the final answer as

<h3>1 atm</h3>

Hope this helps you

5 0
3 years ago
Calculate the PH of a solution 0.030 MH2SO4
Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

4 0
3 years ago
6. An object is in _____________________________ when its distance from a(n) __________________________is changing. 7. Speed in
strojnjashka [21]

<em>Explanation:</em>

<em>Explanation:An object is in motion when its distance from another object is changing. Whether an object is moving or not depends on your point of view. ... A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.</em>

6 0
3 years ago
What is the molarity of a HCl solution, if 28.6 mL of a 0.175 m NaOH solution is needed to neutralize a 25.0 mL sample of the HC
Katen [24]

The molarity of the HCl solution needed to neutralize 28.6 mL of a 0.175 M NaOH solution is 0.2002 M

We'll begin by writing the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

  • From the question given above, the following data were obtained:

Volume of base, NaOH (Vb) = 28.6 mL

Molarity of base, NaOH (Mb) = 0.175 M

Volume of acid, HCl (Va) = 25 mL

<h3>Molarity of acid, HCl (Ma) = ?</h3>

The molarity of the acid, HCl can be obtained as follow:

MaVa / MbVb = nA / nB

(Ma × 25) / (0.175 × 28.6) = 1

(Ma × 25) / 5.005 = 1

Cross multiply

Ma × 25 = 5.005

Divide both side by 25

Ma = 5.005 / 25

<h3>Ma = 0.2002 M</h3>

Therefore, the molarity of the acid, HCl needed for the reaction is 0.2002 M

Learn more: brainly.com/question/25573711

7 0
3 years ago
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