Answer:
[The rate differential results from induced fit on the enzyme upon binding of glucose. This conformational change excludes water from gaining access to the -phosphate group on ATP, and brings the same group close to the OH group on carbon 6 of glucose]
Explanation:
1 mol Cu - 2 mol Ag
x - 0.854 mol Ag
x=0.854*1/2=0.427
0.427 mol Cu
The answer is: B) Spills in your shop and any releases on pavement or outside should be poured down a drain.
Pouring used oil down a drain can cause damege to environment.
Oil is nonpolar substance and does not dissolve in the water (polar molecule), used oil remain existent in the drain and sewer or in the environment.
Small spills create a cumulative effect with significant impact on the environment.
Untended spills inside a shop can spread to an inside drain connected to the storm sewer system and cause floods.
Answer:
7.28 moles Ag°
Explanation:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Given 7.28 moles 7.28 moles
To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...
Limiting reactant determination:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Cu: 7.28 / 1 = 7.28
AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃
Solving Problem depends on AgNO₃; Cu will be in excess.
Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.
