Answer:
The equilbrium constant is 179.6
Explanation:
To solve this question we can use the equation:
ΔG = -RTlnK
<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>
<em>R is gas constant = 8.314x10⁻³kJ/molK</em>
<em>T is absolute temperature = 298K</em>
<em>And K is equilibrium constant.</em>
Replacing:
12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK
5.19 = lnK
e^5.19 = K
179.6 = K
<h3>The equilbrium constant is 179.6</h3>
I believe your answer Is C. An ammonia molecule has a trigonometrical pyramidal shape. Figure C has a <span>has a trigonometrical pyramidal shape.</span>
I hope I help
Answer:
Peatification and coalification
Explanation:
https://energyeducation.ca/encyclopedia/Coal_formation
aswer: protactinium-234 is more dang erous than uranium
