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1 year ago

Which reaction takes place in a nuclear fission reactor?

Chemistry

1 answer:

Marat540 [252]1 year ago

3 0

The reaction that takes place in a nuclear fission reactor is as follows: 235/92 U + 1/0n 94/36Kr + 139/56 Ba + 3/0n.

<h3>What is a nuclear fission reactor?</h3>

A nuclear fission reactor is the place where nuclear chain reactions occur that produce energy by fission.

Nuclear fission is the nuclear reaction in which a large nucleus splits into smaller ones with the simultaneous release of energy.

Therefore, the option that involves the splitting of atoms into smaller ones is as follows: 235/92 U + 1/0n 94/36Kr + 139/56 Ba + 3/0n.

Learn more about nuclear fission reactor at: brainly.com/question/10203508

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BRAINLIEST FOR THE FIRST CORRECT ANSWER!! im revising for a test and my teacher gave me some questions to do but i dont understa

il63 [147K]

Answer:

tensile strength, elongation, flexural strength, and impact resistance.

Explanation:

3 0

2 years ago

A 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12

NISA [10]

Answer:

The answer to this is

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Explanation:

To solve the question, let us list out the given variables and their values

Mass of first marble m1 = 27.3g

Velocity of the first marble v1 = 21.0 cm/s

Mass of second marble m2 = 11.7g

Velocity of the second marble v2 = 12.6 cm/s

After collision va1 = unknown and va2 = 23.7 cm/s

From Newton's second law of motion, force = rate of change of momentum produced

Hence m1v1 + m2v2 = m1va1 + m2va2 or

va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

4 0

3 years ago

How many moles of potassium are in 78.20 g?

Fynjy0 [20]

The answer to this question would be: 2 mol

To answer this question, you need to know the molecular weight of Potassium. Molecular weight determines how much the weight of 1 mol of a molecule has.
Potassium or Kalium molecular weight is 39.1 gram/mol. Then, 78.20gram of potassium should be: 78.20g/ (39.1g/mol)= 2 mol

7 0

3 years ago

Read 2 more answers

Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1

LUCKY_DIMON [66]

Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid hence the answer.

6 0

2 years ago

A potassium bromide solution is 8.30% potassium bromide by mass and its density is 1.03 g/ml. what mass of potassium bromide is

pshichka [43]

<u>Answer:</u> The mass of potassium bromide present in 41.2 mL of solution will be 3.522 grams.

<u>Explanation:</u>

We are given that KBr is present in 8.3% KBr solution, which means that 8.3 grams of potassium bromide is present in 100 gram of the solution.

To calculate the volume of KBr, we use the formula:

$Density=\frac{Mass}{Volume}$

Mass of the solution = 100 grams

Density of KBr solution = 1.03g/mL

Volume of the solution = ? mL

Putting values in above equation, we get:

$1.03g/mL=\frac{100g}{Volume}\\\\Volume=97.08mL$

Now, to calculate the mass of KBr in 41.2mL of the solution, we use unitary method.

In 97.08 mL of solution, mass of KBr present is 8.3 grams.

So, 41.2 mL of solution will contain = $\frac{8.3g}{97.08mL}\times 41.2mL=3.522g$ of KBr.

Hence, the mass of potassium bromide present in 41.2 mL of solution will be 3.522 grams.

7 0

3 years ago