In the following terms
above, the best terms that matches the following are:
RNA - > 2. Nucleic
Acid =RNA is matched to Nucleic Acid
Sucrose - > 3. Carbohydrates
= Sucrose is matched to Carbohydrates
Steroids - > 4. Proteins
= Steroids is matched to Proteins
<span>Toxins - > 1. Lipids
= Toxins is matched to Lipids</span>
Answer:
Explanation:
Cu²⁺ + 2e⁻ → Cu ( copper gets reduced )
Cu → Cu²⁺ + 2e⁻ ( copper gets oxidized )
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Answer:
Explanation:
There are eight isotopes of lawrencium, and they are all radioactive,
I will do the calculation for ²⁶²Lr, which has a half-life of 3.6 h.
Let A₀ = the original amount of lawrencium.
The amount remaining after one half-life is ½A₀.
After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.
After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀, and so on.
We can write a general formula for the amount remaining:
A =A₀(½)ⁿ
where n is the number of half-lives
Data:
A₀ = 5 g
t = 30 min
Calculations:
(a) Convert the half-life to minutes
(b) Calculate n
(c) Calculate A
Answer:
The empirical formula is, C4H4S
Explanation:
Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles
Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g
Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles
Mass of hydrogen = 0.025 moles × 1 = 0.025 g
Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles
Mass of sulphur= 0.0064 moles ×32 = 0.2 g
Now we obtain the mole ratios by dividing through by the lowest ratio.
C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles
C4H4S
Answer:
6.02 * 10^23 (aka Avogadro's number)
Explanation:
