<u>Answer:</u> The nuclear fission reaction of U-234.043 is written below.
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
For the given fission reaction:
<u>To calculate A:</u>
Total mass on reactant side = total mass on product side
234.043 = 137.159 + A + 3(1.0087)
A = 93.858
Now, the chemical equation becomes:
Hence, the nuclear fission reaction of U-234.043 is written above.
For the data set 1, 1, 2, 5, 6, 6, 9 the median is 5. For the data set 1, 1, 2, 6, 6, 9 the median is 4.
hope it helps you
So you have to multiply 786,3 times 0.98 to get the mass the mass is 770.57 if u round its 770.6 or 771
Answer:
26.56g
Explanation:
The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.
For the problem, when 1 half life transcur, the sample has a mass of:
425g / 2 = 212.5g
When 2 half lives transcur:
212.5g / 2 = 106.25g
3 half lives:
106.25/2 = 53.13g
And the amount that is found after 4 half lives is:
53.13/2 =
<h3>26.56g</h3>
