The atom is krypton and its symbol is Kr.
the mass number is 41 + 36 = 77
its charge is 0 as it is a noble gas.
Answer:
source Mass extinctions are episodes in which a large number of plant and animal species become extinct within a relatively short period of geologic time—from possibly a few thousand to a few million years. ... Permian Period — 252 million years ago. Devonian Period — 359 million years ago. Ordovician Period — 443 million years
BP: Nowadays, scientists are aware of five mass extinction events in the past, starting with the End-Ordovician Extinction 450 million years ago and up to the End-Cretaceous Extinction that killed off the dinosaurs 66 million years ago
<u>In your own words- Mass extinctions area unit episodes during which an oversized variety of plant and animal species become extinct at intervals a comparatively short amount of earth science time—from probably some thousand to some million years. ... Permian period — 252 million years past. period — 359 million years past. geological period — 443 million years</u>
<u>BP: today, scientists area unit alert to 5 mass extinction events within the past, beginning with the End-Ordovician Extinction 450 million years past and up to the End-Cretaceous Extinction that killed off the dinosaurs sixty six million years past </u>
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Explanation:
source is where i got this information and the in your own words is it fully rewritten hope this helps and my aplogies for making this so lengthy!
Answer:
the correct answer:
C, B, D, A.
Explanation:
The chemical compounds named are compounds that have strong chemical bonds, forming cubic structures and crystals with very high boiling and melting points to less solid structures.
some are oxides, others salts, others are even used to emit radiation.
Answer:
Hence mass of 2 moles of NaCl is 117g. The molar mass of NaCl is 58.44 g/mol. To calculate mass in grams, multiply the given moles by the molar mass.
<u>Ans: Volume of stock H2SO4 required = 6.94 ml</u>
<u>Given:</u>
Concentration of stock H2SO4 solution M1 = 18.0 M
Concentration of the final H2SO4 solution needed M2 = 2.50 M
Final volume of H2SO4 needed, V2 = 50.0 ml
<u>To determine:</u>
Volume of stock needed, V1
Explanation:
Use the dilution relation: