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tatiyna
3 years ago
15

How many electrons in the same atom can share the quantum number n = 2?

Chemistry
1 answer:
melisa1 [442]3 years ago
3 0
With the principle quantum number being 2, the maximum number that can share this is 8. You can use the general formula 2n^2 to calculate this number (n=quantum level), or you can use the concept of quantum numbers (n, l, m, s) to justify this answer.
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vovangra [49]

Answer:

1. an object that has been intentionally placed into orbit. they are called Artificial Satalites.Satanists.

2. a huge collection of gas ,dust and billions of stars and their solar systems held together by gravity.

3. a large object such as Jupiter or Earth that orbits a star. planets are smaller than stars and they do not produce light.

4. July 16, 1969

7 0
3 years ago
How would you determine which isotope pair to use for a particular material?
VLD [36.1K]

Answer:

Different types of isotopes are used for different materials or objects. For radiometric dating, uranium-235 is considered best for it while carbon-14 is used for dating of rocks. It is also used for dating of wood samples.

Explanation:

Carbon-14 and uranium-235 are used for different materials or objects for measuring the age of these materials. These two isotopes are radioactive in nature which means they emit gamma radiations which allow us to find the age of different objects. Carbon-14 has a low half life so it can be used for those objects which are present before thousands of years while uranium-235 is used for materials which are millions of years old due to high half life.

7 0
3 years ago
Calculate the average atomic mass for the following element given information about the relevant isotopes: (Isotope 1) Mass = 20
polet [3.4K]

Answer:

The average atomic mass of given element is 20.18 amu.

Explanation:

Given data:

Abundance of 1st isotope mass 20 amu = 90.92%

Abundance of 2nd isotope mass 21 amu = 0.257%

Abundance of 3rd isotope mass 22 amu = 8.82%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (90.92×20)+(0.257×21)+(8.82×22) /100

Average atomic mass =  1818.4 + 5.397 +194.04 / 100

Average atomic mass  = 2017.819 / 100

Average atomic mass = 20.18 amu.

The average atomic mass of given element is 20.18 amu.

5 0
3 years ago
If 38.6 grams of iron react with an excess of bromine gas, what mass of FeBr2 can form?
Yuki888 [10]

Answer:

›› FeBr2 molecular weight. Molar mass of FeBr2 = 215.653 g/mol. This compound is also known as Iron(II) Bromide. Convert grams FeBr2 to moles or moles FeBr2 to grams. Molecular weight calculation: 55.845 + 79.904*2 ›› Percent composition by element

Explanation:

5 0
3 years ago
How many grams of KCl (s) has been produced from the thermal decomposition of KClO3 (s) that produced 50.0 mL of O2 (g) at 25 de
geniusboy [140]

Answer:

The mass is m_{KCl} =  0.102 \ g

Explanation:

From the question we are told that

   The volume of oxygen produced is  V_o = 50mL  = 50 *10^{-3} L

    The temperature is T = 25 ^oC = 25* 273 = 298 K

     The pressure is  P = 1.0\  atm

From the ideal gas law we have that

      PV =  nRT

Where R is the gas constant  with the value

         R =  0.08206 \ atm \cdot L /mol K

  n is the number of moles making it the subject of the formula

          n = \frac{PV}{RT}

Substituting values

          n = \frac{1 * (50 *10^{-3}) }{0.08206 * 298}

          n =  2.045 *10^{-3} \  mol

From the chemical equation

      one mole of  KClO_3 produces one mole of  kCl and   \frac{3}{2} of oxygen

       x mole of  KClO_3 produces x mole of  kCl and   2.045 *10^{-3} \  mol of oxygen

So    x = \frac{2.045 *10^{-3}}{\frac{3}{2} }

      x =  \frac{2}{3} * 2.045 *10^{-3}

      x =  1.363 *10^{-3} \ mol

Now the molar mass of  KCl is a constant with a value

           M_{KCl} = 74.55  g/mol

Now the mass of KCl is mathematically evaluated as

          m_{KCl} = x * M_{KCl}

Substituting values

          m_{KCl} = 1.363 *10^{-3} * 74.55

         m_{KCl} =  0.102 \ g

6 0
3 years ago
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