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3 years ago

the air pressure was 101.3 kPa, but the weatherman said it was 1001.3 kPa. What is the percentage error

Chemistry

1 answer:

Andrew [12]3 years ago

5 0

Answer:

percentage error = 888.45 %

Explanation:

We calculate the percentage error using the following formula:

percentage error = [(estimated number - actual number) / actual number) × 100

percentage error = [(1001.3 - 101.3) / 101.3] × 100

percentage error = 888.45 %

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How many moles are in 2.5L of 1.75 M Na2CO3

Natasha_Volkova [10]

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

$M=n/V$

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

$n=V*M$

Thus, we plug in the given data to obtain:

$n=2.5L*1.75mol/L=4.4mol$

Best regards!

4 0

2 years ago

Read 2 more answers

Baking soda NaHCO3, is made from soda ash, a common name for sodium carbonate. The soda ash is obtained in two ways. It can be m

Vaselesa [24]

Answer:

Explanation:

From the given information:

mass of silver chloride AgCl = 11.89 g

molar mass of AgCl = 143.37 g/mol

We know that:

number of moles = mass/molar mass

∴

number of moles of AgCl = 11.89 g/ 143.37 g/mol

number of moles of AgCl = 0.0829 mol

The chemical equation for the mineral called trona is:

$\mathsf{Na_2CO_3.NaHCO_3.2H_2O}$

when being reacted with hydrochloric acid, we have:

$\mathsf{Na_2CO_3.NaHCO_3.2H_2O + 3HCl \to 3NaCl + 2CO_2 +4H_2O}$

One mole of NaCl formed from one mole of trona sample = 0.0829 moles of AgCl

i.e. 0.0829 moles of NaCl can be formed from AgCl

mass of trona sample = number of moles × molar mass

mass of trona sample = 0.0829 × 226

mass of trona sample = 18.735 g

The mass in the percentage of NaHCO₃ = mass of NaHCO₃/ mass of trona

The mass in the percentage of NaHCO₃ = 6.93/18.735

The mass in the percentage of NaHCO₃ = 0.36989

The mass in the percentage of NaHCO₃ = 36.99%

Nonetheless, a 6.78 g samples manufactured from sodium carbonate in pure 100%

∴

6.78 g sample manufactured from Na₂CO₃ is purer.

8 0

3 years ago

In the following reaction, H3PO4 (aq) + H2O (l) ⇄ H2PO4– (aq) + H3O+ (aq) what happens when more H2PO4– (aq) is added to the sol

kirza4 [7]

Answer:

The concentration of H₃PO₄ will increase.

Explanation:

H₃PO₄(aq) + H₂O(l) ⇄ H₂PO₄⁻(aq) + H₃O⁺(aq)

According to Le Châtelier's Principle, when we apply a stress to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

If we add more H₂PO₄⁻, the position of equilibrium will move to the left to get rid of the added H₂PO₄⁻.

The concentration of H₃PO₄ will increase.

7 0

3 years ago

A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al

hodyreva [135]

Answer:

$0.384\ \text{L}$

Explanation:

$P_1$ = Initial pressure = 931 torr = $931\times \dfrac{101.325}{760}=124.12\ \text{kPa}$

$P_2$ = Final pressure = 113 kPa

$V_1$ = Initial volume = 350 mL

$V_2$ = Final volume

From the Boyle's law we have

$P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}$

The volume the gas would occupy is $0.384\ \text{L}$ .

3 0

2 years ago

Convert 72g of O2 to moles

Volgvan

Moles = mass / molar mass
molar mass of O2 is 32
therefore moles = 72/32
= 2.25 moles

4 0

3 years ago

Read 2 more answers

the air pressure was 101.3 kPa, but the weatherman said it was 1001.3 kPa. What is the percentage error​

the air pressure was 101.3 kPa, but the weatherman said it was 1001.3 kPa. What is the percentage error