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alexira [117]
3 years ago
11

How to turn Standard Form (-2x + 3y = -12) to Point-slope Form?

Mathematics
1 answer:
IgorC [24]3 years ago
5 0
It would be <span>a slope of -2.</span>
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the two cycles have center G where radius GI= 4ft, radius MG =6.5ft and MGC=72. Determine the total cost be to paint area MCAI i
Solnce55 [7]
I have no clue what the answer would be, I’ve worked on it for 25 minutes, I will get back to you if I figure it out :,)
4 0
3 years ago
How many different right triangles are there with a hypotenuse of lenght 5 cm
Sveta_85 [38]

Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

ABC is a right triangle with hypotenuse 5. Do this again with a point a little closer to the 3 O’Clock position. It’s another right triangle with hypotenuse 5.

Indeed, as you get closer to the right, along the arc, the height of the triangle declines, but the width of the triangle increases. The hypotenuse remains 5 in all cases. We picked points on the circle. We could have picked points on the horizontal line first, and raised perpendicular lines until they intersected the circle. Each point forms a distinct right triangle.

There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

6 0
3 years ago
Their is a rectangle that has measurements in inches. If the width is 7/8 of an inch and the height is 2/3 of an inch, what is t
Alex Ar [27]

Answer:

Area of a rectangle = 7/12 of an inch

Step-by-step explanation

Area of a rectangle = Length × width

In this case, the length is represented by height

Height = 2/3 of an inch

Width = 7/8 of an inch

Area of a rectangle = Length × width

= 2/3 × 7/8

= (2 * 7) / (3 * 8)

= 14 / 24

= 7 / 12

Area of a rectangle = 7/12 of an inch

7 0
3 years ago
A cone has radius 3.8 cm and height 7.6 cm. The radius and the height are doubled. Which of the following describes the effect o
TiliK225 [7]

Answer:

The volume is multiplied by 8.

Step-by-step explanation:

The volume of a cone with a radius of 3.8 and a height of 7.6 is 114.92. Now let’s double them, the results come out to be 919.39, we divide these by each other and we get roughly 8 when you round. Therefore, your answer is 8.

8 0
3 years ago
Can I see how long division works on these? pls no sketchy links
alexandr1967 [171]

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

          ________________

2v - 2 |  2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

          <u>              v²                </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

          <u>              v²    -7v       </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v

repeat again

<u />

          <u>              v²  -  7v  -  7 </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v + 13

                            <u>-(-14v + 14)</u>

                                          -1

and remainder gets put over the divisor and appended

v²  -  7v  -  7 - 1/(2v - 2)

13) Same process

          <u>                                      </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>              8a²                 </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

          <u>              8a² -    4a     </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                   -(-<u>20a² -   4a)</u>

                                -35a - 5

          <u>              8a² -    4a  - 7  </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                    -(<u>20a² -   4a)</u>

                                -35a - 5

                              -<u>(-35a - 7)</u>

                                           2

8a² - 4a - 7 + 2/(5a + 1)

5 0
3 years ago
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