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3 years ago

What is the answer???

Mathematics

1 answer:

nexus9112 [7]3 years ago

6 0

Try this, I think its correct

$y= 4(x- \frac{7}{8})^{2}+ \frac{159}{16}$

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9/17 15/34 6/17 9/34 geometric sequence?

zysi [14]

In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

9/17 = 18/34
15/34
6/17 = 12/34
9/34

Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.

This would match the definition of an arithmetic sequence and NOT a geometric sequence.

6 0

3 years ago

The attendance at a seminar in year 1 was 500. In year 2, the attendance changed by 100. What was the percent change in attendan

Citrus2011 [14]

Answer:

20%

Step-by-step explanation:

to figure this out yourself you could simply do 100/500 = 0.2 which translates to 20%

3 0

3 years ago

Out of 431 applicants for a job, 142 have over 5 years of experience and 103 have over 5 years of experience and have a graduate

Savatey [412]

Answer:

0.2390

Step-by-step explanation:

<u>Given</u>

Total applicants = 431
Applicants with graduate degree and over 5 years of experience = 103

Probability = favorable outcomes/total outcomes

<u>Required probability </u>

103/431 = 0.2390 rounded to 4 decimal places

3 0

4 years ago

A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41).

aniked [119]

$\frac{(x-h)^{2} }{a^{2} } - \frac{(y - k)^{2} }{b^{2} } = 1$

$\frac{(x-0)^{2} }{40^{2} } - \frac{(y - 0)^{2} }{b^{2} } = 1$

a² + b² = c²

40² + b² = 41²

b² = 41² - 40²

b² = 1681 - 1600

b² = 81

b = 9

slope (m) of asymptote = $+/-\frac{y}{x} = +/-\frac{b}{a} = +/-\frac{9}{40}$

y-intercept (b) = 0 since the center is at the origin

Answer: y = $\frac{9}{40}x$ and y = $-\frac{9}{40}x$

7 0

3 years ago

Read 2 more answers

How would you solve this equation? Please show steps

Serhud [2]

Simple....

you have: $3x= \sqrt{12-12x}$

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>

$(3x)^{2} = \sqrt{12-12x} ^{2}$

Leaving you with....

$9x^{2} =12-12x$

Move the terms over and set it equal to zero.

-->>

$9x^{2}+12x-12=0$

Factor out a 3...

$3( 3x^{2} +4x-4=0)$

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...

$3(3x-2)(x+2)=0$

Remember you're solving for 0....

3x-2=0

3x-2=0
+2 +2

3x=2

$\frac{3x}{3} = \frac{2}{3}$

x= $\frac{2}{3}$

Then-->>

x+2=0

x+2=0
-2 -2

x=-2

Thus, your answer.

4 0

3 years ago