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3 years ago

What is the answer???

Mathematics

1 answer:

nexus9112 [7]3 years ago

6 0

Try this, I think its correct

$y= 4(x- \frac{7}{8})^{2}+ \frac{159}{16}$

You might be interested in

Use the functions f(x) and g(x) to answer the question. F(x)=x²-16; g(x)=x+4

AnnZ [28]

(x^2) - 16 / x+4 = (x-4)(x+4) / (x+4) = x-4, x not equal to -4

D is the answer.

7 0

3 years ago

Add and simplify: 9/16 + 1/2=?<br> 5/8<br> 7/16<br> 1 1/16<br> 1 5/9

Rina8888 [55]

Answer:

1 1/+6

Step-by-step explanation:

9/16 + 8/16=17/16=1 1/16

5 0

3 years ago

Read 2 more answers

Please Help!!

Genrish500 [490]

Given

$a\sqrt{x+b}+c=d$

we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

7 0

3 years ago

What is the value of 11+3(9-6)-4

Zanzabum

When you simply the expression it’s 16

4 0

3 years ago

Which ordered pair is a solution to the equation 8x - 2y = 4 ?

kipiarov [429]

Answer:

(2, 6)

Step-by-step explanation:

Because 8(2)-2(6)=16-12=4.

6 0

3 years ago