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Alex Ar [27]
3 years ago
13

Which of the following is true about semi-conductors: A. Exposing a crystal of a semiconductor to heat or light starts displacin

g valence electrons which then move throughout the crystal B. A material is classified as a semiconductor if its resistance to the flow of electric current is too low to permit it to be called a conductor C. Neither free electrons nor holes are considered charge carriers in a semi-conductor D. Gold and silver are important semiconductors
Physics
2 answers:
pogonyaev3 years ago
8 0
The answer is b 100%
Dmitry_Shevchenko [17]3 years ago
5 0
<h3 />

B. A material is classified as a semiconductor if its resistance to the flow of electric current is too low to permit it to be called a conductor.

<h3 />
  • Semiconductors contain a forbidden gap between the valence band and the conduction band, in which electrons energy levels are not allowed.
  • The resistance of semiconductors decreases as their temperatures increases, which is opposite to how metals or other conductors behave.
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3 0
3 years ago
What acceleration is produced on a mass of 200g, when a force of 10N is exerted on it?​
n200080 [17]

Answer:

f=ma......10N=0.2a....=50m/s

4 0
3 years ago
A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’
scZoUnD [109]

A charged particle moving in a magnetic field experiences a force equal to:

\vec{F}=q\vec{v}\times \vec{B}

Thus, the magnitude of the force that the proton experiences is given by:

F=qvBsin\theta

The magnetic field is perpendicular to the proton's velocity, therefore, we have \theta=90^\circ. Replacing the given values, we obtain:

F=1.6*10^{-19}C(300\frac{m}{s})(1T)sin(90^\circ)\\F=4.8*10^{-17}N

3 0
3 years ago
A wire has a current density of 6.25 × 10 6 A / m 2 6.25×106 A/m2 . If the cross-sectional area of the wire is 1.79 mm 2 1.79 mm
joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

3 0
3 years ago
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