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Rainbow [258]
3 years ago
14

A current 2a flows in a circuit fir 2 minutes. Calculate the charge generated in a circuit​

Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

the charge generated in the circuit​ is 240 C.

Explanation:

Given;

current flowing in the circuit, I = 2A

time of current flow, t = 2 minutes = 2 x 60s = 120 s

The current flowing through a given circuit is defined as the quantity of charge flowing through the circuit in a given time.

I = \frac{Q}{t} \\\\Q = I t

where;

Q is the charge flowing in the circuit

Q = 2 x 120

Q = 240 C

Therefore, the charge generated in the circuit​ is 240 C.

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Answer:

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As the temperature of water drops, it continues to give off thermal energy until it freezes. This is an example of.
jeka57 [31]

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The answer should be C

Explanation:

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7 0
3 years ago
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Starting from rest, a 2.1x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
nirvana33 [79]

Answer:

1.327363 m/s

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Explanation:

u = Initial velocity

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Energy

E=\frac{1}{2}m(v^2-u^2)\\\Rightarrow 3.7\times 10^{-4}=2.1\times 10^{-4}(v^2-0)\\\Rightarrow v=\sqrt{\frac{3.7\times 10^{-4}}{2.1\times 10^{-4}}}\\\Rightarrow v=1.32736\ m/s

The velocity of the flea when leaving the ground is 1.327363 m/s

W=F\times s\\\Rightarrow s=\frac{W}{F}\\\Rightarrow s=\frac{3.7\times 10^{-4}}{0.41}\\\Rightarrow s=0.00090243\ m

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8 0
3 years ago
Can you help me with my homework please ? Science
geniusboy [140]
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7 0
3 years ago
A chevrolet corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. what
pychu [463]
By definition we have that the final speed is:
 Vf² = Vo² + 2 * a * d
 Where,
 Vo: Final speed
 a: acceleration
 d: distance.
 We cleared this expression the acceleration:
 a = (Vf²-Vo²) / (2 * d)
 Substituting the values:
 a = ((0) ^ 2- (60) ^ 2) / ((2) * (123) * (1/5280))
 a = -77268 mi / h ^ 2
 its stopping distance on a roadway sloping downward at an angle of 17.0 ° is:
 First you must make a free body diagram and see the acceleration of the car:
 g = 32.2 feet / sec ^ 2
 a = -77268 (mi / h ^ 2) * (5280/1) (feet / mi) * (1/3600) ^ 2 (h / s) ^ 2
 a = -31.48 feet / sec ^ 2
 A = a + g * sin (θ) = -31.48 + 32.2 * sin17.0
 A = -22.07 feet / sec ^ 2
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 Vf² = Vo² + 2 * a * d
 d = (Vf²-Vo²) / (2 * a)
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 answer:
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3 years ago
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