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Rainbow [258]
3 years ago
14

A current 2a flows in a circuit fir 2 minutes. Calculate the charge generated in a circuit​

Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

the charge generated in the circuit​ is 240 C.

Explanation:

Given;

current flowing in the circuit, I = 2A

time of current flow, t = 2 minutes = 2 x 60s = 120 s

The current flowing through a given circuit is defined as the quantity of charge flowing through the circuit in a given time.

I = \frac{Q}{t} \\\\Q = I t

where;

Q is the charge flowing in the circuit

Q = 2 x 120

Q = 240 C

Therefore, the charge generated in the circuit​ is 240 C.

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3 years ago
A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T. If the magnetic
larisa86 [58]

Answer:

The charge is moving with the  velocity of 1.1\times10^{4}\ m/s.

Explanation:

Given that,

Charge q =8.4\times10^{-4}\ C

Angle = 35°

Magnetic field strength B=6.7\times10^{-3}\ T

Magnetic force F=3.5\times10^{-2}\ N

We need to calculate the velocity.

The Lorentz force exerted by the magnetic field on a moving charge.

The magnetic force is defined as:

F = qvB\sin\theta

v = \dfrac{F}{qB\sin\theta}

Where,

F =  Magnetic force

q = charge

B = Magnetic field strength

v = velocity

Put the value into the formula

v =\dfrac{3.5\times10^{-2}}{8.4\times10^{-4}\times6.7\times10^{-3}\times\sin35^{\circ}}

v =\dfrac{3.5\times10^{-2}}{8.4\times10^{-4}\times6.7\times10^{-3}\times0.57}

v = 10910.36\ m/s

v = 1.1\times10^{4}\ m/s

Hence, The charge is moving with the  velocity of 1.1\times10^{4}\ m/s.

4 0
3 years ago
Review. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00 mT . The angular momen
Ghella [55]

The speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

The angular momentum(L) of an electron moving in a circular path is given by the formula,

L = mvr ........(i)

We know that the radius of the path of an electron in a magnetic field is

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Putting this value in equation (i),

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Putting the given values in the above equation,

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Hence, the speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

To know more about "angular momentum", refer to the following link:

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