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Andreyy89
3 years ago
9

In the formula for magnetic deflection, FM is equal to qvB. Match each symbol in this formula with what it represents.

Physics
2 answers:
slava [35]3 years ago
8 0

Answer:

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

Explanation:

We are given that magnetic  deflection

F_m=qvB

We have to match each symbol in formula with what it  represents.

In this formula

F_m=Deflection force

q=Charge of particle

v=Velocity of charge

B=Perpendicular magnetic field strength

Therefore,

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

san4es73 [151]3 years ago
5 0

Answer:

F_m=Deflection force

q=Charge of particle

v=Velocity of charge

B=Perpendicular magnetic field strength

Explanation:

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That taxi will traveled 1500s by carrying the passenger.

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3 years ago
An object has a mass of 785 g and a volume of 15 cm³. What is its density? (Give your answer in g/cm³ to 2 decimal places).
Anvisha [2.4K]

Answer:

denisity = 52.33 g/cm^{3}

Explanation:

Density:

d = \frac{m}{v}

We have that m = 785 and that v = 15 cm^{3}.

d = \frac{785}{15}

d = 52.33 m^{3}

4 0
3 years ago
Find the wavelength of the third line in the lyman series, and identify the type of em radiation.
Natalija [7]

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( \frac{1}{(n1)^{2} } -   \frac{1}{(n2)^{2} })

                 = 109678 ( \frac{1}{1^{2} } -  \frac{1}{3^{2} } )

                 = 109678 (8/9)

   Lambda = 9 / (109678 * 8 )

                  = 102.6 * 10^{-9} m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

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8 0
2 years ago
Which of the following quantities is directly proportional to the gravitational pull between two objects? Sum of their volumes P
Furkat [3]

The correct answer is:

Product of their masses


In fact, the gravitational pull between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two objects

r is the distance between the centres of the two objects


From the equation, we immediately see that the gravitational attraction is directly proportional to the product of the masses.

3 0
3 years ago
If a second resistor with R2 = 19.0 Ω is connected in series with R1, what is the total rate at which electrical energy is dissi
luda_lava [24]

Total rate at which electrical energy is dissipated by the two resistors are V²/R  or I²R.

<u>Explanation:</u>

When the two resistors are combined in series then the total resistance gets added.

If R_{1} and R_{2} are in series then total resistance, R =

Total resistance becomes R_{1} + 19 Ω

The total electrical power dissipated is equivalent to the power dissipated.

We know,

Power = V²/R  or

Power = I²R

where, V is the potential difference between the ends

            I is the current supplied.

Therefore, total speed at which electrical power is consumed by the two resistors are V²/R  or I²R.

7 0
3 years ago
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