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UNO [17]
3 years ago
5

Give the (Hawarth projection) cyclic

Chemistry
1 answer:
denpristay [2]3 years ago
8 0

Answer:

a) The cyclic structure of D-fructose is drawn in the attachment

b)The carbons in the ring are 4

c) The diagram is shown in the attachment

d)This can be classified as a reducing agent. This is because it contains aldehyde that are oxidized to carboxylic acid.

e) The D-fructose sugar has anomeric carbon which is an aldehyde or hemiacetal. In fructose, both anomeric carbons are in acetal functional groups

Explanation:

The explanations is attached.

Download pdf
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What are the requirements for combustion of a candle?
cestrela7 [59]
For a candle to burn, it requires a spark, which provides the activation energy for the oxidation reaction of the hydrocarbon making the candle.
It also requires oxygen to facilitate the oxidation of the hydrocarbon.
Therefore the two main requirements of combustion of a candle are oxygen and a spark (or an initial flame)
7 0
3 years ago
Identify the reactant and products in the following chemical reaction: CH4 + 2O2 ➡ CO2 + 2H2O
kap26 [50]

The reactants are methane and oxygen.

The products are carbon dioxide and water.

6 0
3 years ago
What is 25mg in grams
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4 0
4 years ago
H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
4 years ago
The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

6 0
4 years ago
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