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diamong [38]
3 years ago
15

The variables for this experiment include the physical properties of the solutions and the pH of each solution. Use the drop-dow

n menus to complete the sentences and identify the independent and dependent variables. The independent variable, the one that is intentionally manipulated, is . a)the pH of the solutions b) the physical properties c) the system of measurement The dependent variable, the one that you measure the response in, is . a) the pH of solutions b) the physical properties c) the system of measurement

Chemistry
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

here is the answer

Explanation:

Sever21 [200]3 years ago
6 0

Answer:

B,D

Explanation:

In December, a city in the Southern Hemisphere has warm weather all month long.

What causes this to happen?

The city experiences fewer hours of daylight.

The city is experiencing a winter solstice.

There is a high concentration of the Sun’s rays in that region.

The Sun reaches its highest point in the sky during this month.In December, a city in the Southern Hemisphere has warm weather all month long.

What causes this to happen?

The city experiences fewer hours of daylight.

The city is experiencing a winter solstice.

There is a high concentration of the Sun’s rays in that region.

The Sun reaches its highest point in the sky during this month.

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Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at
valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100  - x  

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,  

121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042

120.9038x+122.9042\left(100-x\right)=12176.01

Solving for x, we get that:

x = 57.2 %

<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>

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How many electrons will be in the valence of non- H atoms when they make covalent bonds?
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