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3 years ago

Algebra- Multiple Choice

Mathematics

2 answers:

sasho [114]3 years ago

8 0

B, 8 and 9. 8x and 9x are coefficients

AURORKA [14]3 years ago

7 0

The second choice, 8 and 9 since they’re the numbers being multiplied by a variable.

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A triangular brace has an angle measure of 30 degrees, with a side opposite this angle measuring 8 inches. The base of the trian

Ad libitum [116K]

Answer:

Step-by-step explanation:

according to sine rule,

sin(30)/8=sin(x)/11

solving above equation will give

x=43.3

7 0

3 years ago

Don’t know this one

tatiyna

Answer:

Step-by-step explanation:

The answer is B because in order for the square root of a number to be equal to another number, the answer squared should be the number under the square root.

8 0

3 years ago

Read 2 more answers

Perimeter of a rectangle is 96m. if it's length is 3 times it's width , then find it's length and breadth.

Stolb23 [73]

Answer:

breadth = 12

length = 36

Step-by-step explanation:

let the breadth be 'x'

length = 3x

p = 2l + 2b

96 = 2(3x) + 2(x)

x = 12

7 0

3 years ago

PLS HELP!!! FIRST ANSWER GETS BRAINLIEST!!!

olga55 [171]

Answer:C

Step-by-step explanation:11m is the radius and to find the diameter u multiply 11 x 2 which is radius x 2 which = 22

5 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago