Answer:
what? what's the full question?
We first assume that this gas is an ideal gas where it follows the ideal gas equation. The said equation is expressed as: PV = nRT. From this equation, we can predict the changes in the pressure, volume and temperature. If the volume and the temperature of this gas is doubled, then the pressure still stays the same.
Answer:
Option C
Explanation:
When you perform a experiment to test your hypothesis (your educated guess on what you think will happen) you complete trials to find data that is reliable and valid so you are only getting the best possible results. After you complete the experiment you write your conclusion which is when you take the data and you say if the data supported your hypothesis, if you did guess correctly at the beginning of the experiment. Which means the answer is option C "the conclusions tell why the data support or reject the hypothesis."
Hope this helps.
Answer:
2l- ---> l2 + 2e- is the anode
2H+ + 2e- ---> H2(g) is the cathode
Explanation:
Oxidation occurs when a metal loses two or more electrons in a redox chemical reaction and reduction is when it gains. Thus, oxidation is the anode and reduction is the cathode.
Answer:
[H⁺] = 1.0 x 10⁻¹² M.
Explanation:
∵ [H⁺][OH⁻] = 10⁻¹⁴.
[OH⁻] = 1 x 10⁻² mol/L.
∴ [H⁺] = 10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.
∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.
∴ The solution is basic, since pH id higher than 7 and also the [OH⁻] > [H⁺].
I think- IDK
